B.E.

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New answer posted

a year ago

0 Follower 4 Views

A
Atul Mishra

Beginner-Level 1

As per the data available, Median package of B.E. / B.Tech course is around INR 500,000.

New answer posted

a year ago

0 Follower 3 Views

A
Atul Mishra

Beginner-Level 1

As per the data available, Median package of B.E. / B.Tech course is around INR 380,000.

New answer posted

a year ago

0 Follower

A
Atul Mishra

Beginner-Level 1

As per the data available, Median package of B.E. / B.Tech course is around INR 350,000.

New answer posted

a year ago

0 Follower

A
Atul Mishra

Beginner-Level 1

As per the data available, Median package of B.E. / B.Tech course is around INR 525,000.

New answer posted

a year ago

0 Follower 19 Views

Shiksha Ask & Answer
Moderator_ Shiksha

Contributor-Level 10

To apply for admission at Marwadi UniversityVisit the Marwadi University websiteClick on the "Apply Online" button.Fill in the required details in the application form.Upload the necessary documents, such as 10th and 12th certificates, mark sheets, and other relevant documents.Pay the application fee through the available payment options.Submit the application form.The admission process for Marwadi University varies depending on the program. For undergraduate admissions, the primary basis is academic merit. For BE admission, students need to have a valid GUJCET or JEE Main score. BArch applicants must have a valid NATA score. For MBA c
...more

New answer posted

a year ago

0 Follower 10 Views

J
Janvi Pathak

Beginner-Level 5

Courses like MBA BBA BCA and B.Tech provide decent package here. But general course like B.A. does not provide good package 

New answer posted

a year ago

0 Follower 5 Views

D
Deepkaur

Contributor-Level 7

The selection criteria for the Bachelor of Engineering programme at RajaRajeswari College of Engineering is based on merit in the qualifying examination. Candidates who have passed 10+2 or equivalent examination with a minimum of 45% marks in Physics, Chemistry, and Mathematics as compulsory subjects are eligible for admission. However, for the Computer Science branch, candidates should have passed Bachelor's degree/B.Tech in Computer Science with at least 50% marks (45% for reserved category) in the qualifying examination. The selection process is based on the merit list prepared by the college.

New answer posted

a year ago

0 Follower 6 Views

Shiksha Ask & Answer
Mohit Singh

Contributor-Level 8

The highest package offered by Noida Institute of Engineering and Technology (NIET) for the B.E./B.Tech course is not fixed and can vary based on factors such as the specific engineering branch and the year of admission. As per the most recent data available, in the year 2020, the highest package recorded was approximately 12 LPA, and this figure was specifically for the Computer Science and Engineering branch. It's essential to note that these figures may change annually due to various factors, including industry trends and the performance of graduating students.

New answer posted

a year ago

0 Follower 9 Views

Shiksha Ask & Answer
Mohit Singh

Contributor-Level 8

To secure admission to Noida Institute of Engineering and Technology (NIET) for B.E./B.Tech programs, start by visiting the institute's official website. There, you'll find the application form, which requires your academic credentials, entrance exam scores (such as JEE Main or UPSEE), and other pertinent information. Typically, the application process commences around April/May annually. For further assistance and clarifications, don't hesitate to get in touch with NIET's admission office. This direct approach ensures a smooth and well-guided admission procedure.

New answer posted

a year ago

0 Follower 16 Views

D
Dev Garg

Contributor-Level 6

Round 3 cutoff for  WBJEE 2023  at Techno India University is 42319 to 95816.  The closing ranks for all B.Tech.programs ranged from 42319 to 95816. The favourite computer Science and engineering, closed with a rank of 42319.An alternative to WBJEE is  JEE Mains  which is also the way to get a seat at Techno India University for computer science. The overall cutoff  for JEE-Mainis 89555–295479. If you want to tke admission the a rank under 90k will work.

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