Colleges in Orissa

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a year ago

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Aayushi Bijawe

Contributor-Level 10

 IIT Bhubaneswar, JEE-Advanced Cutoff 2022 for General Category is listed below. The overall cutoff for JEE-Advanced is 2486 - 6789 rank. The overall cutoff for JEE-Advanced is 2486 - 12852 rank. Note: The cutoff varies every year, and the above cutoff is only for reference purposes.

New answer posted

a year ago

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R
Rashmi Sinha

Contributor-Level 10

The last year 2022 cutoff ranks for B.Tech. in Civil Engineering + M.Tech. in Transportation Engineering at IIT Bhubaneswar - Indian Institute of Technology other than General category are - 5008 for OBC, 2628 for SC, 2050 for EWS. While the admissions are based on the scores/rank obtained in JEE exam, the last cut offs also change a lot depending on All India quota or Home State. It also varies if the applicant is a female.

New question posted

a year ago

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New answer posted

a year ago

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L
Liyansha Jain

Contributor-Level 10

For last year, the closing rank for Integrated BSc + MSc in Chemistry was 54745 which is very close to this range. This was for General category under All India quota. Unless the candidate belongs to some other category or domicile, one cannot afford to score less than this. With this rank, there is a probability of getting admission. However, the cut offs keep changing year on year, it's advisable to try to score better ranks to increase your chances of getting admission to various courses at NIT Rourkela - National Institute of Technology.

New answer posted

a year ago

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L
Liyansha Jain

Contributor-Level 10

Opening and Closing rank depends on the category and quota of candidates. For General category under All India, opening rank was 25494 and closing rank was 43498. Cut offs are different when it comes to other categories or female candidates and even domicile of home state. In All India, opening and closing rank for female candidates was 25048 and 59818. Admission to BTech +M.Techin Chemical Engineering at NIT Rourkela - National Institute of Technology is based on the scores obtained in the entrance exams like JEE. Applicants are advised to first confirm the category in which they are applying and then check the cut-offs.

New answer posted

a year ago

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L
Liyansha Jain

Contributor-Level 10

NIT Rourkela - National Institute of Technology will release around 6 to 8 rounds of JEE Main cutoffs for admission to BTech. The cutoffs will be released on a rolling basis, and the seats will be filled on a first-come, first-served basis. The cutoffs will be based on the following factors:-The JEE Main score of the candidate-The category of the candidate-The number of seats available in the courseCandidates must visit the official website of entrance exam to read clear instructions on how to proceed with the counselling process, once the round is released.

New answer posted

a year ago

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L
Liyansha Jain

Contributor-Level 10

Opening and Closing rank depends on the category and quota of candidates. For General category under All India, opening rank was 35655 and closing rank was 65106. Cut offs are different when it comes to other categories or female candidates and even domicile of home state. Admission to BTech +M.Techin Ceramic Engineering at NIT Rourkela - National Institute of Technology is based on the scores obtained in the entrance exam like JEE. Applicants are advised to first confirm the category in which they are applying and then check the cut-offs.

New answer posted

a year ago

0 Follower 2 Views

L
Liyansha Jain

Contributor-Level 10

The cutoff trend for the BTech at NIT Rourkela - National Institute of Technology is seen to be decreasing in recent years. In 2021, the closing rank for BTech under the General category for all India quota was 48630. In 2022, it decreased to 41669. Likewise, the cut off ranks have changed from 59378 to 52928 for OBC, 147690 to 140794 for SC, 208976 to 143477 for ST, 55149 to 54081 for EWS. This trend is likely to continue in the coming years, as the demand for Engineering education in India continues to grow. A similar cut-off trend can be seen for female candidates under all categories however the ranks are slightly different.

New answer posted

a year ago

0 Follower 3 Views

L
Liyansha Jain

Contributor-Level 10

For last year, the closing rank for BTech in Ceramic Engineering was 41669 which is very close to this range. This was for General category under All India quota. Unless the candidate belongs to some other category or domicile, one cannot afford to score less than this. With this rank, there is a probability of getting admission. However, the cut offs keeps changing year on year, it's advisable to try to score better ranks to increase your chances of getting admission to BTech in Ceramic Engineering at NIT Rourkela.

New answer posted

a year ago

0 Follower 9 Views

L
Liyansha Jain

Contributor-Level 10

The last year 2022 cutoff ranks for BTech in Biotechnology at NIT Rourkela - National Institute of Technology for other than General category are - 51154 for OBC, 97614 for SC, 1649 for ST, 49797 for EWS, and 1974 for PWD. While the admissions are based on the scores/rank obtained in JEE exam, the last cut offs also change a lot depending on All India quota or Home State. It also varies if the applicant is a female.

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