Colleges in Rourkela
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New answer posted
6 years agoContributor-Level 6
New answer posted
6 years agoBeginner-Level 3
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6 years agoGuide-Level 12
Hope this helps.
All the best.
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor?utm_source=cconnect&utm_medium=CR_JEECP&utm_campaign=6375912
New question posted
6 years agoNew answer posted
6 years agoGuide-Level 13
Please check this link after inserting your rank and category. Use the filter option, and click on search button.
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor#
Hope your query is resolved.
For any other query, please feel free to ask me.
Best of luck.
New answer posted
6 years agoContributor-Level 8
It is a new branch at NIT Rourkela, as it has a deep scope for development and research, so it would grow more and more in the mean time. Moreover, it is something that you would enjoy studying, if you really have any interest in production and processing of Food and maintaining its quality.
More likely, this branch is all about food making, no it is way broader. We develop food, we develop machines to develop food, we develop machines to keep the food safe. So it has certain degree of mechanical engineering, certain degree of chemical engineering and a major part of Food Science and Engineering.
As there is growth and development in
New answer posted
6 years agoContributor-Level 8
Congratulation for your good score. The eligibility criteria for getting admission into NIT Rourkela or into any of the NITs is For General candidates to qualify for admissions to NITs/IIITs/GFTIs, they should have secured at least 75% marks in class 12th exam or be in the top 20 percentile in class 12th exam conducted by the respective boards. For SC/ST candidates, the eligibility criteria is 65% marks in class 12th. Other than that according to the past records, the JEE rank for Electronics engineering 7000-8000. So there is a good opportunity for you to get admission in the your preferred branch. You can get admission in NIT Rour
New answer posted
6 years agoContributor-Level 8
To get admission in NIT Rourkela, For General candidates to qualify for admissions to NITs/IIITs/GFTIs, they should have secured at least 75% marks in class 12th exam or be in the top 20 percentile in class 12th exam conducted by the respective boards. For SC/ST candidates, the eligibility criteria is 65% marks in class 12th.The Home State: Rank - 16679 And Other State: Rank - 12898 for mechanical engineering.
The placement of the mechanical branch is quite good at NIT Rourkela. Core companies like Tata steel, Vedanta, Tata motors, Maruti - Suzuki, Mahindra & Mahindra and many more visit our campus every year and recruit meritorious s
New answer posted
6 years agoContributor-Level 8
Both Food processing and industrial design are different. So it solely depend on you that if you are interested to know the techniques behind food processing as well as gain knowledge for it then just move on for food processing engineering in NIT Rourkela. It is a new branch started in NIT Rourkela and very soon it has gained tremendous popularity in the mean time. It has hold a good placement record instead of a new branch. The placements of NIT Rourkela is good. The average placement of the college is around 6-7 LPA. Mostly, all the student got placed. Last year, the highest package was 29 LPA which is offered by Amazon. Many cor
New answer posted
6 years agoContributor-Level 8
Well, for getting admission into the college NIT Rourkela, you need to qualify class 12 board exam and the JEE Mains exam. Based on your score and rank you can apply for any branch of your interest in NIT Rourkela. The criteria For candidates to qualify for admissions to NITs/IIITs/GFTIs, they should have secured at least 75% marks in class 12th exam or be in the top 20 percentile in class 12th exam conducted by the respective boards,for General students. For SC/ST candidates, the eligibility criteria is 65% marks in class 12th.The rank in JEE Mains should be Home State: Rank - 25570 and Other State: Rank - 16412 . NIT Rourkela is r
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