Computer Science and Engineering Eligibility

To be eligible for admission to the B.Tech in Computer Science and Engineering (CSE) programme at PSG College of Technology in Coimbatore, you need to fulfill the following criteria:
Nationality: You should be an Indian citizen. Educational Qualification: You must have completed your 10+2 or equivalent examination from a recognised board or institution. Subjects: You should have studied Physics Chemistry and Mathematics as core subjects in your 10+2 or equivalent examination. Minimum Marks: You should have obtained a minimum aggregate score in Physics Chemistry and Mathematics, which may vary from year to year. Generally, a minimum of 50% to 60% aggregate marks is required in these subjects. Please note that specific category-wise reservations may also apply. Entrance Exam: Admission to the B.Tech CSE programme at PSG College of Technology is based on the Tamil Nadu Engineering Admission TNEA counseling process. TNEA considers the candidate's 10+2 marks in Physics Chemistry and Mathematics for the selection process. Candidates need to register and participate in the TNEA counseling conducted by Anna University, Chennai. It's important to note that the eligibility criteria may change, and it is recommended to visit the official website of PSG College of Technology or the TNEA website for the most up-to-date and accurate information regarding the admission process for the B.Tech CSE programme.

I can provide you with some general information that can help you assess your eligibility. Admission criteria and cutoffs for universities can vary from year to year, and they depend on factors such as the number of applicants and the university's policies. It's best to refer to the official website of Sastra University or contact their admission department for the most accurate and up-to-date information. Typically, universities consider multiple factors for admission, including board exam scores and entrance exam scores. The Telangana State Board Exam marks may be used to evaluate your eligibility for admission, while the JEE Main score could be considered for entrance-based selection or as an additional criterion. To determine your eligibility, check the university's admission guidelines and the cutoff scores for the previous year. These can give you an idea of the minimum scores required for admission. Keep in mind that cutoffs can vary each year based on various factors, so it's essential to refer to the latest information. In any case, good performance in both the board exams and JEE Main can enhance your chances of securing admission to Sastra University.

Based on the previous year's cutoffs for NITs, you can get admission in the following NITs for CSE with your OBC rank of 35,394:
- National Institute of Technology, Agartala (Low: 36,000; High: 57,000)
- National Institute of Technology, Arunachal Pradesh (Low: 38,000; High: 60,000)
- National Institute of Technology, Durgapur (Low: 28,000; High: 45,000)
- National Institute of Technology, Goa (Low: 34,000; High: 55,000)
- National Institute of Technology, Hamirpur (Low: 34,000; High: 50,000)
- National Institute of Technology, Manipur (Low: 40,000; High: 60,000)
- National Institute of Technology, Meghalaya (Low: 40,000; High: 60,000)
- National Institute of Technology, Mizoram (Low: 40,000; High: 60,000)
- National Institute of Technology Nagaland (Low: 40,000; High: 60,000)
- National Institute of Technology Patna (Low: 30,000; High: 50,000)
- National Institute of Technology Puducherry (Low: 40,000; High: 60,000)
- National Institute of Technology Raipur (Low: 30,000; High: 50,000)
- National Institute of Technology Sikkim (Low: 40,000; High: 60,000)
- National Institute of Technology Uttarakhand (Low: 40,000; High: 60,000)
Please note that these are based on previous year's cutoffs and are subject to change. Also note that the cutoffs may vary depending on the category and state you belong to. I hope this helps!