Jaypee University of Information Technology

The eligibility criteria for admission to B.Tech programme at JUIT Solan is as follows:1. Passed 10+2 or equivalent examination from a recognised board with Physics, Chemistry, and Mathematics as compulsory subjects with a minimum of 60% aggregate marks (55% for SC/ST candidates).2. Candidates appearing in the qualifying examination in March/April are also eligible to apply, provided they submit the mark sheets by the specified date.3. Candidates who have cleared the Diploma (Engineering & Technology) examination with at least 60% marks (55% for SC/ST candidates) are also eligible to apply.So, if you have scored 70% in your class 12th examinations, you are eligible to apply for B.Tech programme at JUIT Solan. However, the final selection will be based on your performance in the entrance exam and counseling process.

The minimum eligibility criteria for B.Tech admission at Jaypee University of Information Technology (JUIT) in 2023 are as follows:Candidates must have completed their 10+2 (or equivalent) with a minimum of 60% aggregate marks to be eligible for admission to B.Tech programs.Candidates must have appeared in JEE Main 2023 or CUET (UG) 2023 and secured a valid score/rank.The cutoff for different branches of B.Tech may vary depending on the availability of seats and the number of applicants. The cutoff for CSE branch goes around 1.6 Lakh, for IT and ECE it goes around 2.5 Lacs and for civil it goes for around 5 Lakh.For more information, you can visit the official website of JUIT or Shiksha. I hope this helps.

Jaypee University of Information Technology, established in 2002 is a state university, located in Solan, Himachal Pradesh. The college was established by the Government of Himachal Pradesh and Founder Chairman of Jaypee Group. JUIT, Solan is approved by the UGC (University Grants Commission), AICTE (All India Council for Technical Education) and PCI (Pharmacy Council of India). Jaypee University of Information Technology is accredited by the NAAC (National Assessment and Accreditation Council).A candidate can check the JUIT Solan cutoff 2023 by visiting the official website of the university. The cutoff is based on the performance of the candidates in the entrance exams such as JEE, CUET, PGET, or GATE, depending on the program. The cutoff may vary for different categories of candidates and different branches of study. I hope this information helps you. 

JUIT Solan is a private university in Himachal Pradesh that offers various programmes in engineering, computer science, biotechnology, bioinformatics, physics and more. Some of the unique features of JUIT Solan are:It is ranked among the top engineering colleges in India by various agencies such as QS, THE, NIRF and SCImago.It has received several accreditations and recognitions for its academic excellence, innovation and campus life.It has filed and granted 23 patents in various fields of research and innovation.It has achieved impressive placements for its students, with the highest salary package of 44.14 Lacs by Amazon in 2023.It has a scenic campus in the foothills of the Himalayas, with state-of-the-art facilities and infrastructure.

JUIT Solan offers admission to various undergraduate, postgraduate and doctoral programmes. For B.Tech admission, you can apply either through JEE Main score or merit in 10+2 examination. For M.Tech admission, you need to appear for GATE or Post Graduate Entrance Test (PGET) conducted by JUIT. GATE qualified candidates can apply directly.Non-GATE candidates should clear the PGET conducted by the JUIT.GATE candidates and students with excellent academics shall be eligible for the Teaching Assistantships, provided they meet the minimum CGPA requirement.10% seats in JUIT Solan are reserved for candidates who have qualified their 10+2 examination from Himachal Pradesh.For M.Sc and Ph.D admission, you need to have a relevant degree with minimum marks and clear the entrance test or interview conducted by JUIT.For more information, you can visit the official website of JUIT or Shiksha. Hope this helps you

The minimum eligibility criteria for B.Tech admission at Jaypee University of Information Technology (JUIT) in 2023 are as follows:Candidates must have completed their 10+2 (or equivalent) with a minimum of 60% aggregate marks to be eligible for admission to B.Tech programs.Candidates must have appeared in JEE Main 2023 or CUET (UG) 2023 conducted by JUIT.The cutoff for different branches of B.Tech may vary depending on the availability of seats and the number of applicants. The cutoff for CSE branch goes around 1.6 Lakh, for IT and ECE it goes around 2.5 Lacs and for civil it goes for around 5 Lakh.For more information, you can visit the official website of JUIT or Shiksha.