JEE Main Scores
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5 years agoContributor-Level 9
New answer posted
5 years agoScholar-Level 18
New answer posted
5 years agoContributor-Level 9
So, if I assume you a NCL candidate, then about 120 is enough to get admission in any of the NITs.
New answer posted
5 years agoScholar-Level 18
Many other students too are interested in knowing their percentile figures. Unfortunately even if it is simple to calculate it, in present scenario it's not feasible. This is so since we must know maximum and minimum marks scored by students in that shift besides total number of students who appeared. Only NTA can do it. Please have patience. Results are expected in any case by the end of this month. Best wishes to you.
New answer posted
5 years agoScholar-Level 18
Almost all colleges in Mumbai give admission based on MHT CET and not on JEE Mains. Hence you must appear for this exam and score good marks. A very miniscule percent seats are reserved for "All India Quota" and these are filled up using JEE Mains. Hence cut off marks for JEE Mains has no relevance.
New answer posted
5 years agoContributor-Level 9
According to 2018 record the closing rank for CS Engineering is 30k and for mechanical engineering is 40k.
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5 years agoContributor-Level 7
Kindly specify which university/college you wish to apply in.
New answer posted
5 years agoScholar-Level 18
I can understand the anxiety, the desire and the angst of a student to know his results in percentile based on the marks that he could make out from the answer keys displayed by National Testing Agency. However, it is next to impossible for a layman or anybody for that matter, except for NTA to find out the percentile based on marks obtained. This is so because for calculation of percentile one needs to know the total number of students appeared for that particular shift as well as the minimum and maximum marks scored in that particular shift. This information is available only with NTA and as a result, they only wil
New answer posted
5 years agoContributor-Level 6
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