JEE

Preparing for the chemistry section of the JEE exam requires a strategic approach. Here's a guide to help you excel:Understand the Syllabus:JEE Chemistry is divided into three sections: Physical, Organic, and Inorganic Chemistry. Go through the detailed syllabus and focus on high-weightage topics.Build Strong Fundamentals:Start with understanding the basic concepts thoroughly. Chemistry requires a clear understanding of fundamental concepts to tackle complex problems.Books & Resources:Physical Chemistry: "Physical Chemistry" by P. Bahadur or O.P. Tandon.Organic Chemistry: "Organic Chemistry" by Morrison and Boyd.Inorganic Chemistry: "Concise Inorganic Chemistry" by J.D. Lee.Practice Regularly:Solve a variety of problems from previous years and mock tests. Practicing will enhance your problem-solving speed and accuracy.Time Management:Manage your time effectively. Divide your study schedule between theory, problem-solving, and revision. Don't neglect any section.Revision & Mock Tests:Regular revision and taking mock tests will help you track your progress. Analyze your mistakes and work on weak areas.Understand Concepts in Organic and Inorganic Chemistry:Focus on reaction mechanisms in Organic Chemistry and periodic trends, and molecular orbital theory in Inorganic Chemistry.CHEMISTRY IS ALL ABOUT REVISING AGAIN AND AGAIN!

With an 82.42 percentile in JEE Mains, you have several good options for engineering colleges in Maharashtra. Here are some of the top colleges where you might get admission:SGGS College of Engineering and Technology, NandedNagesh Karajagi Orchid College of Engineering and Technology (NKOCET), SolapurWalchand College of Engineering, SangliG. H. Raisoni Institute of Engineering and Technology, NagpurK. J. Somaiya Institute of Engineering and Information Technology, MumbaiThese colleges have varying cutoffs each year, so it's a good idea to check the latest cutoff trends and participate in the counseling process. You can also use online college predictor tools to get a more accurate list of colleges based on your rank.

Exam Pattern for JEE Mains is as follows:Mode of Examination:The mode of examination would be as Computer Based Test (CBT).Subjects:The examination would be based on three subjects, i.e. Physics, Chemistry, and Mathematics.Number of Papers:There are two papers under JEE Mains: Paper 1 (for B.E./B.Tech) and Paper 2 (for B.Arch/B.Planning).Paper 1 is CBT based for B.E./B.Tech aspirants. For B.Arch/B.Planning there is both CBT and pen-paper based Paper 2. Paper 1: B.E./B.TechType of Questions: Multiple choice questions (MCQs) and Numerical Value based Question. Total No. of Questions: 90 (30 questions from each subject) Marking Scheme: For MCQs: +4 for correct answers, -1 for incorrect answers. For Numerical Value based Questions: +4 for correct answers; no negative marking for incorrect answers. Total Marks: 300 marks (100 marks per subject). Duration: 3 hours. Paper 2: B.Arch/B.Planning: Part 1: Mathematics (Objective type) Part 2: Aptitude Test (Objective type). Part 3: Drawing Test (B.Arch candidates only) - pen/pencil mode. Marking Scheme: Similar to Paper 1 (+4 for correct answers, minus marking for MCQ). Total Mark: 400. Duration: 3 hours, including Drawing Test. Language of Exam: Exam to be conducted in English, Hindi, and Gujarati. Eligibility Criteria: He/She should be passed/appearing for his/her 12th exam in the ongoing year. There is an upper limit of age while considering the JEE Mains eligibility, which is 25 years for the general category (with a relaxation for reserved categories). JEE Mains are the first stage of the Joint Entrance Examination, and the candidates who successfully complete the first phase can go to the second phase of JEE Advanced for seeking admission into the IITs.

Admission to SASTRA University for engineering programs is highly competitive and follows a unique admission process. Here's an analysis of your chances based on your JEE Mains percentile (89) and CBSE board marks (72%):SASTRA University Admission Process:SASTRA University admits students through two streams:Stream 1:70% of seats are filled based on a combined weightage of:JEE Main score (75% weightage)Class 12th marks (25% weightage).Stream 2:30% of seats are filled based on Class 12th board exam marks alone.This stream is typically for candidates who have not appeared for JEE or have lower scores in JEE.Your Case:Stream 1:Your 89 percentile in JEE Main is a strong point.However, your 72% in CBSE boards might slightly lower your overall weighted score for Stream 1.Admission to core branches like CSE, ECE, and Mechanical is highly competitive, and a higher combined score is typically required for these branches.You may have better chances in branches like Civil Engineering, Biotechnology, or Chemical Engineering.Stream 2:For admission through Stream 2 (based on board marks only), your 72% marks may make it challenging to secure admission in highly sought-after branches. However, you might have a chance in lesser competitive branches.Factors Influencing Admission:State of Residence:SASTRA reserves seats for candidates from Tamil Nadu and neighboring states. If you are from these states, your chances may improve.Category:SASTRA does not provide specific reservations for categories, as admissions are based purely on merit.Demand for Branches:Highly demanded branches like CSE, ECE, and IT usually require higher scores.Next Steps:Calculate Weighted Score for Stream 1:Use the formula: Weighted Score= (0.75*JEE Score)+ (0.25*Class 12 Percentage)\text {Weighted Score} = (0.75 \times \text {JEE Score}) + (0.25 \times \text {Class 12 Percentage})Weighted Score= (0.75*JEE Score)+ (0.25*Class 12 Percentage) Example: Assuming 89 percentile in JEE (converted to marks ~220/300): Weighted Score= (0.75*220)+ (0.25*72)=180+18=198\text {Weighted Score} = (0.75 \times 220) + (0.25 \times 72) = 180 + 18 = 198Weighted Score= (0.75*220)+ (0.25*72)=180+18=198Check Previous Year Cutoffs:Look for cutoffs specific to the branch and stream you're targeting. Cutoffs vary each year based on the competition and demand.Apply Early:Submit your application as early as possible, as SASTRA follows a transparent and rank-based allocation process.Likely Outcome:With 89 percentile in JEE Main, you have a reasonable chance of securing admission in non-core branches through Stream 1.Through Stream 2, admission is less likely due to relatively lower board marks unless applying for less competitive branches.For precise details, visit the official SASTRA University admissions page or contact their admissions office.

As an SC candidate with a 51 percentile in JEE Mains, you have some advantages for IPU B.Tech admission:Eligibility HighlightsSC candidates get a 5% relaxation in minimum marks requirementMinimum marks requirement reduced from 55% to 50%Eligible for B.Tech admission through JEE MainsAdmission DetailsAdmission based on JEE Mains scoreCounselling will determine final college allocationCandidates can get admission in various B.Tech specializations like:Computer ScienceArtificial Intelligence & Data ScienceAutomation & RoboticsIndustrial Internet of ThingsKey RecommendationsParticipate in IPU counselling processBe prepared for multiple rounds of seat allocationKeep documents ready for verificationConsider all available specializations. 

No, you can't get admission into a B.Tech Mechanical Engineering programme at Banaras Hindu University (BHU) without the Joint Entrance Examination (JEE): EligibilityTo be eligible for admission to B.Tech programs at IIT BHU, you must meet the eligibility criteria set by JEE Main and JEE Advanced. This includes passing Class 12 with a minimum aggregate of 75% (or 65% for SC/ST/PwD candidates). Admission processAdmission to B.Tech programs at IIT BHU is based on the candidate's performance in the JEE. You must register for the JoSAA counseling process and fill in your preferences for IITs. JoSAA will then allocate seats based on your JEE Advanced rank and preferences.