NIT Surathkal - National Institute of Technology Eligibility
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New answer posted
5 years agoGuide-Level 12
New answer posted
5 years agoGuide-Level 12
New answer posted
5 years agoContributor-Level 8
Above is the possible rank you can get. The final rank will be based on the best of the scores of JEE-Mains January 2019 and April 2019 exam. The predicted rank may vary due to JEE Main tie breaker rules for same score. For information on the list of colleges eligible based on this prediction, follow the link below
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor.
New answer posted
5 years agoContributor-Level 6
New answer posted
6 years agoContributor-Level 8
Above is the possible rank you can get. The final rank will be based on the best of the scores of JEE-Mains January 2019 and April 2019 exam. The predicted rank may vary due to JEE Main tie breaker rules for same score.
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor
Kindly visit the above link for the list of eligible colleges.
New answer posted
6 years agoContributor-Level 8
Above is the possible rank you can get. The final rank will be based on the best of the scores of JEE-Mains January 2019 and April 2019 exam. The predicted rank may vary due to JEE Main tie breaker rules for same score.
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor
Kindly visit the above link for the list of eligible colleges.
New answer posted
6 years agoNew answer posted
6 years agoGuide-Level 13
You can input the details in the below link to find out which colleges you can get:
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor?utm_source=connect&utm_medium=CR_JEECP&utm_campaign=6375912
Accordingly, you can take the decision.
New answer posted
6 years agoContributor-Level 6
CS - 2000
Civil - 30000
Mechanical - 40000
Please do share your interested branch of engineering so that I can help you in detail.
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