SASTRA (Deemed to be University) Thanjavur Answered Questions

Yes, you may be eligible for admission to the CSE/ECE branch at SASTRA Thanjavur/Kumbakonam campus with 969 marks in +2 grade and 62% in JEE Mains if you meet the following requirements: You passed the +2 exam with a minimum aggregate of 60% in Physics, Mathematics, and Chemistry/Bio-Technology/Computer Science/BiologyYou took the JEE Main examYou are not more than 20 years of age as of August 1, 2025SASTRA calculates its own ranks for admission based on +2 marks and JEE (Main) scores. Applicants are advised to submit their JEE scores even if they are not qualified for the Advanced or they don't have the cut-off prescribed by MHRD

Securing a place in SASTRA University may pose some challenges with a 64 percentile in JEE Mains and 77% in your CBSE board exams. Admission is usually very high on JEE Mains score for direct admissions due to the specific standard set by the university, but it may be possible to gain admission through the CBSE board for direct counseling. The eligibility in this case will depend on the cutoffs which change for each academic year. So, it is better to either check out its official admission site or contact them for directed advice.

B. Tech in Computer Science and Engineering viz; SASTRA University-Admittance of Thanjavur is purely merit-based, which includes Class 12 marks and JEE Main. While the cutoff goes up and down with years, it is observed that those with better JEE Main ranks and equally good Class 12 marks stand a better chance of getting in. Most often, competitive ranks will be at play, and preference will be given to people with good academic performance. The tuition fees for B. Tech, in general, are INR about 1,50,000 in a year with an increase of about 5%, annually. Accommodation costs differ with regards to the hostel as well as mess fees. One can be able to find the most accurate cutoff details from official sources of SASTRA university.

However, candidates can get admission to SASTRA University for various courses except in B Tech course without JEE scores as the university accepts other entrance tests and 12 standard marks. Currently if your AIR is 12000 and TNR rank in stream 2 is 4839, then probabilities depend on the course and branch chosen. Different B.Tech courses are provided in SASTRA University and the intake fees vary between INR 1,60000 to INR 200000 per annum. The university also provides scholarships for deserving students, the best students are offered full tuition fees exemptions. In this case, this means that even if there is a meeting of the eligibility, there is no guarantee of being given the admission.

Hi Zarana,The admission to the B.B.A., LL.B. (Hons.) program at Kirit P. Mehta School of Law, NMIMS Mumbai is based on entrance exams such as NMIMS LAT or CLAT. The cutoff varies each year depending on the number of applicants and difficulty level of the exam.Eligibility Criteria:10+2 Qualification: Minimum 50% marks in 12th standard from a recognized board.Entrance Exam: A valid score in NMIMS LAT or CLAT.Admission Process:1 Register and apply for NMIMS LAT on the official website.2 Appear for the exam and secure the required score.3 Shortlisted candidates will be called for further selection rounds.For exact cutoff details, visit the official NMIMS website or contact the admissions office. Hope this helps! ? Let me know if you need more details. Best wishes! 

The LL.M. in Criminal Law at Crescent School of Law (CSL) has the following fee structure:Tuition Fee: INR 50,000 per semesterAmenities and Service Fee: INR 20,000 (one-time payment at the time of admission)Transport Charges: Optional, ranging from INR 40,000 to INR 50,000 per year, based on distance and mode of transport.

Admission to SASTRA University for engineering programs is highly competitive and follows a unique admission process. Here's an analysis of your chances based on your JEE Mains percentile (89) and CBSE board marks (72%):SASTRA University Admission Process:SASTRA University admits students through two streams:Stream 1:70% of seats are filled based on a combined weightage of:JEE Main score (75% weightage)Class 12th marks (25% weightage).Stream 2:30% of seats are filled based on Class 12th board exam marks alone.This stream is typically for candidates who have not appeared for JEE or have lower scores in JEE.Your Case:Stream 1:Your 89 percentile in JEE Main is a strong point.However, your 72% in CBSE boards might slightly lower your overall weighted score for Stream 1.Admission to core branches like CSE, ECE, and Mechanical is highly competitive, and a higher combined score is typically required for these branches.You may have better chances in branches like Civil Engineering, Biotechnology, or Chemical Engineering.Stream 2:For admission through Stream 2 (based on board marks only), your 72% marks may make it challenging to secure admission in highly sought-after branches. However, you might have a chance in lesser competitive branches.Factors Influencing Admission:State of Residence:SASTRA reserves seats for candidates from Tamil Nadu and neighboring states. If you are from these states, your chances may improve.Category:SASTRA does not provide specific reservations for categories, as admissions are based purely on merit.Demand for Branches:Highly demanded branches like CSE, ECE, and IT usually require higher scores.Next Steps:Calculate Weighted Score for Stream 1:Use the formula: Weighted Score= (0.75*JEE Score)+ (0.25*Class 12 Percentage)\text {Weighted Score} = (0.75 \times \text {JEE Score}) + (0.25 \times \text {Class 12 Percentage})Weighted Score= (0.75*JEE Score)+ (0.25*Class 12 Percentage) Example: Assuming 89 percentile in JEE (converted to marks ~220/300): Weighted Score= (0.75*220)+ (0.25*72)=180+18=198\text {Weighted Score} = (0.75 \times 220) + (0.25 \times 72) = 180 + 18 = 198Weighted Score= (0.75*220)+ (0.25*72)=180+18=198Check Previous Year Cutoffs:Look for cutoffs specific to the branch and stream you're targeting. Cutoffs vary each year based on the competition and demand.Apply Early:Submit your application as early as possible, as SASTRA follows a transparent and rank-based allocation process.Likely Outcome:With 89 percentile in JEE Main, you have a reasonable chance of securing admission in non-core branches through Stream 1.Through Stream 2, admission is less likely due to relatively lower board marks unless applying for less competitive branches.For precise details, visit the official SASTRA University admissions page or contact their admissions office.

If you are on a merit rank of 6000 for both Stream 1 and Stream 2 of SASTRA then your chances would depend on the programme and branch one is applying for. In past testing SASTRA University has admitted students with ranks below 8000-10000 in Stream 1 & 5000-7000 in Stream 2. Till date, the university has provided nearly 2400 seats in various streams of B.Tech. The details of the fee structure of B.Tech programme in SASTRA University are as follows: It approximately costs from one Lacs sixty thousand to two Lacs for each B.Tech programme per year. However, a rank of 6000 will definitely be competitive and though the candidate will meet all the requirements of the eligibility criteria, he may still not be selected for admission because of other reasons.

 I currently can't provide direct brochures. However, you can find the latest brochure and detailed information regarding lateral entry for the B.E. programme in Electrical and Electronics Engineering (EEE) at SASTRA University on their official website.I recommend visiting the SASTRA University admissions page or contacting their admissions office directly to obtain the most accurate and updated brochure.Would you like a link to their official website or help with anything else?