JEE Mains Expected Cut off 2025: Check how much score is required for admission to top colleges
JEE Main Result 2025 Session 1 will be announced by February 12. Candidates can check here the JEE Main 2025 minimum marks required to qualify for JEE Advanced exam, and JEE Mains expected cutoff 2025. Also check JEE Main closing ranks for admission to top NITs in India.
JEE Main cutoff is the minimum marks required to qualify to appear in JEE Advanced exam for admission to IITs. Candidates can check here the minimum marks required in JEE Mains 2025 to qualify for JEE Advanced. The minimum JEE Mains cutoff marks will be different for every category.
NTA conducted the JEE Mains 2025 session 1 exam from January 22 to 30. JEE Main Answer key 2025 session 1 and response sheet was released on February 4. Candidates can download the answer key and calculate their scores in exam. Candidates not satisfied with the NTA answer can also challenge the JEE Mains 2025 answer key up to February 6 (9 pm).
JEE Mains session 1 result date is February 12. NTA will announce the JEE Main result 2025 session 1 online on the website jeemain.nta.nic.in.
JEE Main Cutoff for JEE Advanced 2025
The minimum JEE Main 2025 marks required to qualify for JEE Advanced will be announced along with the session 2 result in April. Candidates can check here the JEE Mains expected cut off 2025.
| Category |
JEE Main 2025 Expected Cutoff |
| CRL |
100.0000000 to 92.3362181 |
| OBC-All |
92.2312696 to 79.6457881 |
| SC-All |
92.2312696 to 62.0923182 |
| ST-All |
92.2312696 to 47.6975840 |
| UR-PwD |
92.2041331 to 0.0015700 |
JEE Main Cutoff for Top NITs
Candidates can check here the cutoff ranks required for admission to top NITs in India. The closing ranks provided here are last round open category All India rank.
| Institute |
Course |
Last Round Closing Rank |
| NIT Allahabad |
BTech CS |
4191 |
| BTech EE |
10928 |
|
| NIT Jaipur |
BTech CS |
4711 |
| BTech EE |
13170 |
|
| NIT Bhopal |
BTech CS |
8830 |
| BTech EE |
20334 |
|
| NIT Trichy |
BTech CS |
1224 |
| BTech EC |
3546 |
Read More: JEE Main Answer Key, Result 2025 Session 1 Live Updates
Q: What is NIT Rourkela cutoff for BTech?
Q: How to calculate percentile in JEE?
NTA uses a formula to calculate NTA score in JEE Main. The formula used is
Q: What is the expected NIT Calicut JEE Main cutoff 2024?
Going as per the past three year trends candidates can expect the closing ranks for NIT Calicut JEE Main cutoff 2024 Round 1 Seat Allotment for top specialisations between the following range:
- B.Tech. in Computer Science and Engineering must range between 2717 and 4455
- B.Tech. in Electrical and Electronics Engineering must range between 10612 and 12119
- B.Tech. in Electronics and Communication Engineering must range between 7127 and 7563
- Bachelor of Architecture (B.Arch.) must range between 269 and 316
- B.Tech. in Engineering Physics must range between 16153 and 16430
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