JEE Mains 2025 Result Session 1 Date: Check Expected Percentile vs. Marks

JEE Mains 2025 Result Session 1 Date: Check Expected Percentile vs. Marks

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Sanjana
Sanjana Surbhi
Assistant Manager
New Delhi, Updated on Jan 29, 2025 17:00 IST

JEE Main result 2025 for session 1 is expected to be announced within few weeks after the conclusion of exam. Candidates who appeared for the exam can check JEE Main 2025 result session 1 at the official website. Check expected percentile vs marks here

JEE Mains 2025 Result Session 1 Date

JEE Mains 2025 Result Session 1 Date

JEE Main Result 2025: The National Testing Agency (NTA) will likely to declare the JEE Main 2025 session 1 result by February 12, 2025. As per previous trends, the JEE Mains 2025 results are usually announced within a few weeks after the exam concludes. Candidates who appeared for the exam can check their JEE Main 2025 session result, scores and qualifying status on the official website: jeemain.nta.nic.in or ntaresults.nic.in.

They have to use their application Number, password/date of birth and security pin to check the JEE Main 2025 result session 1. Candidates must note that JEE Main cutoff 2025 and All India Rank will be released along with the session 2 scorecard in April. Those who score above the JEE Main 2025 cutoff will be eligible to appear for the JEE Advanced 2025 exam for admission to IITs.

JEE Mains 2025 Result Session 1 Date

Candidates can check the table to know the JEE Main session 1 result date:

Events

Dates 

JEE Main Result Session 1 Date 

February 12, 2025

JEE Main Session 1 

January 22, 23, 24, 28, 29 & 30, 2025 

JEE Mains 2025 Result Session 1 Expected Percentile vs. Marks

The JEE Mains exam uses a percentile-based scoring system instead of a direct marks-to-rank conversion, ensuring fair evaluation by accounting for candidates' relative performance across different shifts. Candidates can check the table to know the expected JEE Main percentile vs. Marks:

JEE Main Percentile

JEE Main Marks

100 - 99.99989145

300-281

99.994681 - 99.997394

271 - 280

99.990990 - 99.994029

263 - 270

99.977205 - 99.988819

250 - 262

99.960163 - 99.975034

241 - 250

99.934980 - 99.956364

231 - 240

99.901113 - 99.928901

221 - 230

99.851616 - 99.893732

211 - 220

99.795063 - 99.845212

201 - 210

99.710831 - 99.782472

191 - 200

99.597399 - 99.688579

181 - 190

99.456939 - 99.573193

171 - 180

99.272084 - 99.431214

161 - 170

99.028614 - 99.239737

151 - 160

98.732389 - 98.990296

141 - 150

98.317414 - 98.666935

131 - 140

97.811260 - 98.254132

121 - 130

97.142937 - 97.685672

111 - 120

96.204550 - 96.978272

101 - 110

94.998594 - 96.064850

91 - 100

How to check JEE Mains 2025 Result Session 1?

Candidates can go through the steps provided below to know how to check JEE Main session 1 result online:

Step 1: Go to the official website: jeemain.nta.nic.in

Step 2: On the homepage, click on JEE Mains 2025 Result link

Step 3: A login page will be displayed on the screen

Step 4: Enter JEE Main Application Number, password/date of birth and security pin

Step 5: Submit details and JEE Main Result 2025 will appear on the screen

Step 6: Download and take printouts of JEE Main 2025 result for future references

Read More

Q: ย  What is NIT Rourkela cutoff for BTech?

A:

NIT Rourkela cutoff 2024 has been released across various specialisations in opening and closing ranks. NIT Rourkela BTech cutoff 2024 ranged between 2680 and 35593 for the General AI category candidates, wherein BTech in CSE is the most competitive course. The easiest BTech specialisation to secure admission in is B.Tech. in Ceramic Engineering + M.Tech. in Industrial Ceramic Engineering. For a detailed NIT Rourkela branch-wise cutoff 2024, candidates can refer to the table below for the Round 1 cutoff. The cutoff mentioned below is for the General category under the AI Quota.

Course 2024
B.Tech. in Biomedical Engineering 28053
B.Tech. in Ceramic Engineering 34492
B.Tech. in Chemical Engineering 16708
B.Tech. in Civil Engineering 23425
B.Tech. in Computer Science and Engineering 2680
B.Tech. in Electrical Engineering 8770
B.Tech. in Electronics and Communication Engineering 5053
B.Tech. in Mechanical Engineering 13682
B.Tech. in Metallurgical and Materials Engineering 27499
B.Tech. in Mining Engineering 31497
B.Tech. in Biotechnology 27533
B.Tech. in Electronics and Instrumentation Engineering 8646
B.Tech. in Industrial Design 27601
B.Tech. + M.Tech. in Chemical Engineering 18843
B.Tech. in Ceramic Engineering + M.Tech. in Industrial Ceramic Engineering 35593
B.Tech. + M.Tech. in Metallurgical and Materials Engineering 33676
B.Tech. + M.Tech. in Mining Engineering 32461
Bachelor of Architecture (B.Arch.) 439
B.Tech. in Food Process Engineering 34726
B.Tech. in Artificial Intelligence 3880

Q: ย  How much is 120 marks in JEE Mains percentile?

A:

The National Testing Agency (NTA) will declare the JEE Mains result 2025 in the form of percentile scores. Candidates can check here the JEE Main 2025 marks vs percentile data to understand the 120 marks in JEE Main percentile.

As per the last year JEE Main marks vs percentile analysis, 120 marks would be around 95 to 97 percentile. However, the exact JEE Main 2025 percentile marks 120 would vary depending upon the highest number scored by the candidate in a particula shift and the total number candidates appeared in that particular shift. More details about JEE Main marks vs percentile vs rank can be checked to understand in details.

Q: ย  What is the expected NIT Calicut JEE Main cutoff 2024?

A:

Going as per the past three year trends candidates can expect the closing ranks for NIT Calicut JEE Main cutoff 2024 Round 1 Seat Allotment for top specialisations between the following range: 

  • B.Tech. in Computer Science and Engineering must range between 2717 and 4455
  • B.Tech. in Electrical and Electronics Engineering must range between 10612 and 12119
  • B.Tech. in Electronics and Communication Engineering must range between 7127 and 7563
  • Bachelor of Architecture (B.Arch.) must range between 269 and 316 
  • B.Tech. in Engineering Physics must range between 16153 and 16430

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About the Author
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Sanjana Surbhi
Assistant Manager

Sanjana Surbhi has over five years of experience in the online education sector. Drawing from her tenure with ed-tech companies, she infuses her work with a wealth of knowledge from the education realm, lending an i... Read Full Bio

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