B.Tech in CSE (Internet of Things)
- A NAAC accredited
- Private Institute
- Estd. 1996
B.Tech in CSE (Internet of Things) at MIT Moradabad Overview
Duration | 4 years |
Course Level | UG Degree |
Mode of Course | Full Time |
Total Tuition Fees | ₹3.58 Lakh |
Official Website | Go to Website  |
Seat breakup | 60 |
Type of University | Private |
B.Tech in CSE (Internet of Things) at MIT Moradabad Fees
| Fee components | Amount (4 years) |
|---|---|
The fee might include components other than tuition fees.
Tuition fee is calculated on the basis of 1st year. Actual amount may vary | ₹ 3.58 Lakh |
One-time payment includes caution deposit. | ₹ 5,000 |
₹ 3.63 Lakh |
These are based on information available on various sources. Latest values may differ.
B.Tech in CSE (Internet of Things) at MIT Moradabad Placements
| Particulars | Statistics (2023) |
|---|---|
| Median Salary | INR 4.50 Lakh |
Top Recruiters for MIT MoradabadB.Tech in CSE (Internet of Things) at MIT Moradabad Entry Requirements
- N/A
- Read more
A candidate must have passed 10+2 examination with Physics/ Mathematics (Compulsory required) + Chemistry/ BioTechnology / Biology/ Technical Vocational subject (Atleast one) Obtained at least 45% marks (40%marks in case of candidates belonging to reserved category) in the above subjects taken together from recognized board.
- N/A
A candidate who has Passed min. 3 years Diploma examination with at least 45% marks (40% marks in case of candidates belonging to reserved category) subject to vacancies in the First Year, in case the vacancies at lateral entry are exhausted.
B.Tech in CSE (Internet of Things) at MIT Moradabad Cutoffs
2JEE Main round-wise cutoff Rank: (undefined-All India)
| Round | 2024 |
|---|---|
| 1 | 1059766 |
| 2 | - |
| 3 | 841120 |
UPTAC round-wise cutoff Rank: (undefined-All India)
| Round | 2024 |
|---|---|
| 1 | 1059766 |
| 2 | - |
| 3 | 841120 |
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