B.E. in Artificial Intelligence and Data Science
- A NAAC accredited
- Private Institute
- Estd. 2008
B.E. in Artificial Intelligence and Data Science at SITRC Overview
Duration | 4 years |
Course Level | UG Degree |
Mode of Course | Full Time |
Total Tuition Fees | ₹4.19 Lakh |
Average package | ₹5.00 Lakh |
Official Website | Go to Website |
Seat breakup | 60 |
Type of University | Private |
B.E. in Artificial Intelligence and Data Science at SITRC Fees
Fee components | Amount (4 years) |
---|---|
Tuition fee is calculated on the basis of 1st year/semester. Actual amount may vary.
Mentioned fee is as per Fee Regulating Authority, Maharashtra State. | ₹ 4.19 Lakh |
₹ 4.19 Lakh |
These are based on information available on various sources. Latest values may differ.
B.E. in Artificial Intelligence and Data Science at SITRC Highlights
- Institute have ICT enabled Smart Spacious Classrooms with State of the Art Laboratories and digital Library
- Institute provides with experienced, qualified and dedicated faculty team
B.E. in Artificial Intelligence and Data Science at SITRC Placements
Particulars | Statistics (2021) |
---|---|
Average Salary | INR 5.00 Lakh |
Highest Salary | INR 12.00 Lakh |
Median Salary | INR 1.92 Lakh |
B.E. in Artificial Intelligence and Data Science at SITRC Frequently Asked Questions
Q: What to do after JEE Main session 2 result?
Candidates preparing for IITs are only required to appear for the JEE Advanced entrance exam after qualifying JEE Main. Students who who secure above the 98th percentile in JEE Main 2024 Session 2 should start preparing for JEE Advanced 2025 immediately. Those who score between 95th and 98th percentile should focus on improving their JEE Main score by taking multiple mock tests and practicing previous year's question papers. By analysing their strengths and weaknesses, candidates can identify their areas of proficiency and topics where they need improvement. If they can achieve full marks in their practice sessions, they can start preparing for JEE Advanced. However, if they cannot score full marks, it is recommended that they appear for multiple mock test series for more practice.
Q: What is the expected JEE Main cutoff 2024?
NIT Manipur JEE Main cutoff 2024 has been released for admission to the BTech courses. During the Round 1 cutoff, the closing rank for CSE was 25886 for the General category students under the AII India Quota. Among OBC candidates, the closing rank for B.Tech. in Computer Science and Engineering stood at 8750. Candidates seeking admisison to NIT Manipur can refer to the table below to check out the Round 1 closing ranks for BTech in CSE course for various categories under the AI quota:
Category | JEE Main 2024 Expected Cutoff |
---|---|
Common Rank List | 90-91 |
Gen-EWS | 75-76 |
OBC-NCL | 73-74 |
SC | 51-52 |
ST | 37-38 |
PwD | 0.0013527 |
Q: Does Sandip Institute of Technology and Research Centre has good and experienced faculty?
Q: Who are the top recruiters from Sandip Institute of Technology and Research Centre when it comes to placements?
Q: What is the median package of B.E. / B.Tech course that is offered by Sandip Institute of Technology and Research Centre?
B.E. in Artificial Intelligence and Data Science at SITRC Entry Requirements
B.E. in Artificial Intelligence and Data Science at SITRC Cutoffs
JEE Main round-wise cutoff Rank: (General-All India)
Round | 2022 | 2023 | 2024 |
---|---|---|---|
1 | 319438 | 186708 | 210472 |
2 | 190623 | - | 193581 |
3 | - | 180532 | 186337 |
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Q: Is Sandip Institute of Technology and Research Centre a good college/Institute?
Q: How is the infrastructure at Sandip Institute of Technology and Research Centre? What are the facilities available for students?
Q: How is the placement facility at Sandip Institute of Technology and Research Centre?
Q: What is the eligibility to get admission in Sandip Institute of Technology and Research Centre for UG/PG courses?
Courses | Eligibility |
---|---|
B.E. / B.Tech | Candidate must have completed Diploma Course in Engineering and Technology in relevant stream with minimum 45% marks (40% marks in case of candidates of Backward class categories and Persons with Disability belonging to Maharashtra State only) from an All India Council for Technical Education or Central or State Government approved Institution or its equivalent. OR Candidate must have completed B.Sc. from UGC/ Association of Indian Universities recognised University with at least 45% marks (40% in case of candidates of Backward class categories and Persons with Disability belonging to Maharashtra State only) and passed 10+2 with Mathematics as a subject. |
M.E./M.Tech | Sponsored candidate must have minimum of two years of full time work experience in a registered firm/ company/ industry/ educational and/ or research institute/ any Government Department or Government Autonomous Organization in the relevant field in which admission is being sought. |
MBA/PGDM | Candidate must have completed minimum three year Bachelor's Degree in any discipline or its equivalent with above mentioned marks (45% in case of candidates of backward class categories and Persons with Disability belonging to Maharashtra State only) from any of the Universities recognised by UGC or AIU. |
Q: What is the median salary of M.E./M.Tech course available at Sandip Institute of Technology and Research Centre?
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B.E. in Artificial Intelligence and Data Science at SITRC Contact Information
Sandip Institute of Technology & Research Center, Trimbak Road
Nashik ( Maharashtra)
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