Electric Flux: Overview, Questions, Preparation

Physics Current Electricity 2023

Updated on Apr 12, 2021 07:12 IST

Electricity is a fundamental force of nature that plays a crucial role in our daily lives. From powering our homes to driving technological advancements, electricity is a cornerstone of modern society. To comprehend the intricate aspects of electricity, it is essential to delve into concepts such as electric flux. In this article, we will explore the concept of electric flux, its significance, and its application in various contexts, catering specifically to Class XII CBSE Board students.

Introduction to Electric Flux:

Electric flux is a concept that helps us understand the flow of electric field lines through a given surface. It is a vital concept in electromagnetism that assists in quantifying the amount of electric field passing through a particular area. The electric field is a vector field that surrounds charged particles and exerts a force on other charged particles within its influence. Electric flux provides a way to visualize and quantify the interactions between electric fields and surfaces.

Mathematical Representation:

Electric flux through a closed surface

S = q/e 0

q = total charge enclosed by S. The law implies that the total electric flux through a closed surface is zero if no charge is enclosed by the surface.

The net flux through a closed surface is directly proportional to the net charge in the volume enclosed by the closed surface.

Φ = → E.d → A = qnet/ε0

Significance and Applications:

Electric flux is a crucial concept with several practical applications, including:

Capacitors: Understanding electric flux helps explain how capacitors store and release electric charge. The concept is vital for designing and analyzing capacitor systems in various electronic devices.

Electric Field Mapping: Electric flux aids in visualizing and mapping electric fields around charged objects. This visualization is vital in engineering and physics applications.

Electric Field Strength: Calculating electric flux assists in determining the electric field strength near charged objects, facilitating the understanding of interactions between charges.

Gauss's Law: Electric flux is at the heart of Gauss's law, a foundational principle in electromagnetism that simplifies complex charge distributions and electric fields.

Conclusion:

In the realm of electromagnetism, electric flux stands as a significant concept that enables us to comprehend the interactions between electric fields and surfaces. Its mathematical representation and applications, including the profound Gauss's law, make it a cornerstone of electrical engineering and physics. As Class XII CBSE Board students, grasping the concept of electric flux not only enhances your understanding of electricity but also lays a strong foundation for future studies and careers in science and technology. So, delve into the world of electric flux, unravel its intricacies, and embark on a journey of discovery in the realm of electromagnetism.

FAQs on Electric Flux

 

Q: When a glass rod is rubbed with a silk cloth, charges appear on both. A similar phenomenon is observed with many other pairs of bodies. Explain how this observation is consistent with the law of conservation of charge.

A: When two bodies are rubbed against each other, it produces charges of equal magnitude in both the bodies but of opposite in nature. Hence the net charges of the two bodies are zero. When a glass rod is rubbed with a silk cloth, similar phenomena occur. This is as per the law of conservation of energy.

Q: Four point charges q_A = 2 μC, q_B= –5 μC, q_C= 2 μC, and q_D= –5 μC are located at the corners of a square ABCD of side 10 cm. What is the force on a charge of 1 μC placed at the centre of the square?

In the adjoining figure ABCD is a square with sides AB = BC = CD = DA = 10 cm

Diagonals, AC = BD = √102 + 102 = 10√2 cm

AO = OC = DO = BO = 5√2  cm

At the centre of the square ABCD, O, a charge of 1μC

The force of repulsion between the charges placed at A and at O is equal in magnitude but opposite in direction between the charges placed at point C and centre O. Similarly the force of attraction between the charges placed at B & O and D & O will be equal in magnitude but opposite in direction. These charges will cancel each other.

Hence, the net charge at centre O will be zero.

Q: (a) An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not? (b) Explain why two field lines never cross each other at any point?

A:

  • An electrostatic field line is a continuous curve because a charge experiences a continuous force when traced in an electrostatic field. The field line cannot have sudden breaks because the charge moves continuously and does not jump from one point to another.
  • The electric field intensity will show two directions at that point where two filed lines crosses. This is not possible. Hence they do not cross.

Q: Two point charges q_A= 3 μC and q_B= –3 μC are located 20 cm apart in vacuum. (a) What is the electric field at the midpoint O of the line AB joining the two charges? (b) If a negative test charge of magnitude 1.5 ×10^(-9) C is placed at this point, what is the force experienced by the test charge?

A: The situation is represented in the following figure.

where ∈0 = Permittivity of free space = 8.854 X 10-12 C2N-1m-2

This force is directed along the line OA, this is because the negative test charge is repelled by the charge placed at point B but attracted towards point A.

News & Updates

Latest NewsPopular News
qna

Physics Current Electricity Exam

Student Forum

chatAnything you would want to ask experts?
Write here...