How To Calculate JEE Main 2025 Rank From Percentile: Criteria and Method
Joint Entrance Exam (JEE) Main 2025 ( JEE Main )
Registration - 1 Feb '25 - 25 Feb '25
- How to calculate JEE Main rank from percentile
- Can JEE Main rank be calculated from percentile score?
While some experts believe that candidates cannot calculate JEE Main Rank from the percentile score of just one examination, others believe the opposite. Let’s discuss both cases in this article.
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Predict JEE Main CollegesHow to calculate JEE Main 2025 rank from Percentile?
Candidates can analyze their NTA scores and calculate their approximate JEE Main rank through their percentile scores. Here’s how.
Take the total number of candidates who appeared for the JEE Main exam as "N". The exam is conducted in four days in two slots (4 days x 2 slots = 8 sessions in total). So, "S" number of students took the exam in each session. Note that the JEE Main results/scorecard mentions only the NTA score for each subject and not the subject-wise marks secured by candidates. The percentile score is displayed against each of the subjects and the overall percentile score is calculated up to 7 decimals using a pre-determined formula.
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There is a 90% more chance of getting best college recommendations by sharing preferences.| For more information on how JEE Main 2025 Percentile score is calculated, read this article on How to calculate JEE Main 2025 Percentile Score - Know Normalization Process |
So, to convert your JEE Main Percentile into a Rank, you need the following figures:
- Your NTA score
- Total number of students who have appeared for the exam
- Percentage of students below or equal to your marks
- Percentage of students above your marks
- Number of students above your marks
While the data for the first two aspects are easily available, the figures for the other three data points are difficult to find. To calculate these, here's what you need to do.
Q: Is 75 percent marks in class 12 required for JEE Mains?
Q: What is the expected NIT Calicut JEE Main cutoff 2024?
Going as per the past three year trends candidates can expect the closing ranks for NIT Calicut JEE Main cutoff 2024 Round 1 Seat Allotment for top specialisations between the following range:
- B.Tech. in Computer Science and Engineering must range between 2717 and 4455
- B.Tech. in Electrical and Electronics Engineering must range between 10612 and 12119
- B.Tech. in Electronics and Communication Engineering must range between 7127 and 7563
- Bachelor of Architecture (B.Arch.) must range between 269 and 316
- B.Tech. in Engineering Physics must range between 16153 and 16430
Q: What is NIT Rourkela cutoff for BTech?
NIT Rourkela cutoff 2024 has been released across various specialisations in opening and closing ranks. NIT Rourkela BTech cutoff 2024 ranged between 2680 and 35593 for the General AI category candidates, wherein BTech in CSE is the most competitive course. The easiest BTech specialisation to secure admission in is B.Tech. in Ceramic Engineering + M.Tech. in Industrial Ceramic Engineering. For a detailed NIT Rourkela branch-wise cutoff 2024, candidates can refer to the table below for the Round 1 cutoff. The cutoff mentioned below is for the General category under the AI Quota.
Let’s assume:
| Your NTA score = |
P |
| Total Number of Students = |
N |
| Percentage of students below or equal to your marks = |
P For example: if you have secured a 70 percentile in JEE Main, which means that 70% of the candidates who appeared for JEE Main are below or at the same level as you are |
| Percentage of students above your marks = |
100 - P |
| Number of students above your marks |
(100 – P)/100)*N |
Now, the formula to calculate JEE Main Rank from Percentile Score is: (100 – P)/100)*N
The rank generated will be the probable All India Rank (AIR) you can expect to secure in JEE Main. The actual rank might differ owing to different factors.
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Can JEE Main rank be calculated from percentile score?
According to an IIT Bombay expert, it’s difficult to derive an AIR through one’s percentile score. To help you understand why you cannot calculate JEE Main rank from percentile scores of the first attempt of the exam, let’s take the example of two students.
| Student |
Percentile Score – January |
Percentile Score – April |
AIR (All India Rank) |
|---|---|---|---|
| A |
96 percentile |
65 percentile |
? |
| B |
60 percentile |
98 percentile |
? |
Student A secured 96 percentile in the JEE Main January exam, while Student B got 60 percentile in the same session of the examination. Now, the same set of students has secured the 65 percentile and 98 percentile respectively in JEE Main.
Now, the general thought process of candidates after seeing the percentile score of the January attempt would be that Student A has performed better than Student B in JEE Main. But, that’s not the case. Because, on the second attempt of the exam, Student B secured a better percentile than Student A. As per NTA, JEE Main ranks or rank list will be published after taking into account the better of the two four NTA scores of all candidates who have appeared for JEE Main January and April sessions. Furthermore, to determine JEE Main results and rank list, the agency will adopt the process of normalization which will be based on percentile calculation. Thus, deriving one’s rank from the percentile score of the first attempt is not possible as the exam is being conducted twice.
Q: What is the cutoff for BTech at NIT Andhra Pradesh for OBC category?
NIT Andhra Pradesh BTech cutoff 2024 for BTech courses ranged between 25704 and 91199 for OBC category. Wherein, the most competitive course was BTech in Computer Science and Engineering and the least competitive course was BTech in Biotechnology. While the admissions are based on the scores/rank obtained in JEE Main, the last cutoffs also change a lot depending on All India quota or Home State. It also varies if the applicant is a female.
Q: How to calculate percentile in JEE?
NTA uses a formula to calculate NTA score in JEE Main. The formula used is
Q: How much is 120 marks in JEE Mains percentile?
The National Testing Agency (NTA) will declare the JEE Mains result 2025 in the form of percentile scores. Candidates can check here the JEE Main 2025 marks vs percentile data to understand the 120 marks in JEE Main percentile.
As per the last year JEE Main marks vs percentile analysis, 120 marks would be around 95 to 97 percentile. However, the exact JEE Main 2025 percentile marks 120 would vary depending upon the highest number scored by the candidate in a particula shift and the total number candidates appeared in that particular shift. More details about JEE Main marks vs percentile vs rank can be checked to understand in details.
Q: Can I get NIT with 95 percentile in JEE Main?
It is possible for you to secure a seat in an NIT (National Institute of Technology), although it may not guarantee your preferred branch or institute. If your percentile is above 96, your chances of getting into a respectable NIT increases, but you may need to compromise on your branch selection. However, if you aim for a decent NIT with a preferred branch in the core field, you would need to score above 97.5%. On the other hand, if your goal is to get admission to a top college with the CSE (Computer Science and Engineering) branch, your score would need to be higher than 99.4%.
Q: Is the NTA percentile score and percentage same?
Important note:
- The percentile is not the same as a percentage.
- JEE Main merit list will be prepared based on percentile scores and not on the raw marks secured by aspirants in the exam.
JEE Main Paper Analysis, Answer Key & Solutions by Experts
Check details expert JEE Main 2023 analysis by Resonance:
| Subject |
Shift 1 |
Shift 2 |
|---|---|---|
| JEE Main 2023 Solutions by Resonance: 06 Apr 2023 |
||
| Maths |
Download PDF | Download PDF |
| Physics |
Download PDF | Download PDF |
| Chemistry |
Download PDF | Download PDF |
| JEE Main 2023Solutions by Resonance: 08 Apr 2023 |
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| Maths |
Download PDF | Download PDF |
| Physics |
Download PDF | Download PDF |
| Chemistry |
Download PDF | Download PDF |
| JEE Main 2023 Solutions by Resonance: 10 Apr 2023 |
||
| Maths |
Download PDF | Download PDF |
| Physics |
Download PDF | Download PDF |
| Chemistry |
Download PDF | Download PDF |
| JEE Main 2023 Solutions by Resonance: 11 Apr 2023 |
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| Maths |
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| Physics |
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| Chemistry |
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| JEE Main 2023 Solutions by Resonance: 12 Apr 2023 |
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| Maths |
Download PDF | Paper 2 was held |
| Physics |
Download PDF | Paper 2 was held |
| Chemistry |
Download PDF | Paper 2 was held |
FAQs regarding JEE Main Percentile and Ranks
Q. Is percentile equal to a percentage?
A. No, percentile and percentage are totally different from each other. The percentile rank of a score is the percentage of scores in its frequency distribution that are equal to or lower than it.
Q. What is percentile vs percentage?
A. The percentile is relative to the score that other people made on the test, while the percentage is your individual score. Percentile is used when scoring standardized tests and is used in statistics.
Q. What is the percentile in JEE Main?
A. JEE Main percentile score will be the normalised score for the exam and not the raw marks of the test taker.
Q. Is 100 percentile possible?
A. If the "percentage below or equal to" definition is used, then, yes, we can have 100 percentile. However, if we use the "percentage below" definition, then, no, you cannot have a 100 percentile.
Q. Can I get nit with 94 percentile?
A. According to your percentile, your approximate rank is 66,000. If you have a home state quota, then you will definitely get an NIT.
Q. Is 97 percentile good in JEE mains?
A. Scoring 97% is good, so, when you are looking for the colleges that you can get at such percentile. It can be an NIT.
Q. Can I get nit with 70 percentile?
A. No, there is no chance to get admission to any NITs with a 70 percentile for the general category. For the general candidates, at least 97 percentile is required to get a seat in NITs. You can try to get admission to other good engineering colleges.
Q. Can I get nit with 90 percentile OBC?
A. You have very low chances of getting admission in any of the NITs based on your JEE Main percentile score and category rank. Try for admission in private colleges through state counselling.
Q. What percentile is required for IIIT?
A. Every year cut off score for IIIT Hyderabad's last closing branch is around 250-260 or 99 percentile, which means a rank of around 1000 will be required for admission.
Q. Is IIIT better than nit?
A. It depends on which IIIT/NIT you are getting according to your rank. In terms of placement, faculties and infrastructure some IIITs are far better than many NITs.
Satyendra is an expert news writer and content editor at shiksha.com with over ten years of experience in the education field. His work involves writing news and articles, editing, and proofreading content related t... Read Full Bio
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Student Forum
Anything you would want to ask experts?Answered 13 hours ago
Inverse Trigonometric Functions is considered a moderated weightage topic, 1 question is expected from this chapter directly. However, ITF plays an important role to boost score through usgae of its properties in Calculus unit, which have a better weightage overall. Students must check the NCERT So
n
Contributor-Level 10
Answered 16 hours ago
With a score of 156 in JEE Mains, you can expect to get admission into several NITs (National Institutes of Technology) for branches other than CSE, and potentially lower ranked NITs or other private engineering colleges for a CSE seat; consider options like NITs in states like Manipur, Goa, Durgapu
D
Beginner-Level 5
Answered Yesterday
Yes, Sushant University welcomes candidates with an admission score using JEE Main for BTech programs. Any candidate must hold a minimum qualification of 50% in the PCM group to be eligible from Class 12. Besides taking the JEE Main, university conducts its BTech entrance AUEE examinations. The entr
a
Contributor-Level 10
Answered Yesterday
Hi Dhivakar,
Based on previous years' data, scoring 53 marks in JEE Main 2024's January 28 Shift 2 is expected to place you in the 70th to 80th percentile range.
This percentile typically corresponds to a rank between 135,695 and 183,105.
Please note that these are approximate figures, and actual perc
A
Contributor-Level 9
Answered 2 days ago
Cutoff Percentiles for JEE MAINS 2025:
General - 95+
Ews - 84+
OBC - 83+
SC - 65+
ST - 50+
It's advisable to regularly check the official JEE Mains website
A
Beginner-Level 2
Answered 2 days ago
While NCERT books can provide a strong foundation for JEE Mains preparation and help you understand basic concepts, they are generally not enough to clear JEE Advanced on their own; you will likely need additional reference books and practice questions to tackle the higher difficulty level of JEE Ad
A
Contributor-Level 10
Answered 2 days ago
To access the 29 January 2025 shift 2 JEE Main paper, you can visit the official NTA website (jeemain.nta.nic.in) or trusted educational platforms like Shiksha and etc. where you can download the question paper PDF with solutions for both shifts of the exam; simply search for "JEE Main 2025 January
D
Beginner-Level 5
Answered 3 days ago
Clearly, JEE main score is completely different from CRL i.e. common rank list.Cut-off for admission to NIT for obc category students varies for every NIT .
R
Beginner-Level 3
Answered 3 days ago
Oftentimes students gain admission to one of over 300 colleges across India through their JEE Mains score performance in which 31 NITs together with 25 IIITs and 28 GFTIs are included. The leading institutions choosing JEE Mains scores as admission criteria include NIT Trichy and NIT Warangal togeth
K
Contributor-Level 10
Answered 3 days ago
Different colleges throughout Bangalore possess varying admitted student cutoff scores for exams including JEE Mains and JEE Advanced. General category students need to score between 85-100 marks while the cutoff requirements for OBC students range from 70-80 percentile and the cutoff values for SC
K
Contributor-Level 7
JEE Main Notifications
Candidates need not have 75 percent marks in class 12 for appearing in JEE Main. As per the official brochure released by the NTA there is no minimum percentage required for appearing in the JEE Main. The requirement of 75 percent marks need not be associated with JEE Main. It is to be understood that 75 percent marks is required for admission to institutes which include NITs, IIITs, GFTIs and IITs. There are many institutes which offer admission on 60% and even less along with JEE Main. Candidates must clearly understand that the requirement of 75 percent marks in class 12 is only for taking admission in the institutes.