The National Testing Agency (NTA) has published the final answer keys of JEE Main 2019 January session for Paper 1 (Physics, Chemistry and Mathematics) on January 23, 2019. The answer keys released are for all the four days that the exam was conducted on - January 9, 10, 11 and 12. The last date to challenge JEE Main 2019 official answer keys, released by NTA on January 15, was January 17, 2019 (upto 11:50 pm). NTA will not entertain anymore more requests to challenge JEE Main 2019 answer keys for the January exam.
Date |
Download final answer keys |
January 9 |
|
January 10 |
|
January 11 |
|
January 12 |
According to JEE Main 2019 final answer keys released, NTA has dropped 22 question and awarded full marks to candidates who appeared for JEE Main 2019 Paper 1 for BTech from January 9 to 12, 2019. Subsequently, two or all four options of some of the questions in the final answer key have been marked as correct.
Explore colleges based on JEE Main
Date |
Shift |
Subject |
Question ID |
January 9 |
Shift 1 |
Physics |
41652910067 |
January 9 |
Shift 2 |
Physics |
41652910157 |
January 10 |
Shift 1 |
Physics |
4165299346 |
January 10 |
Shift 1 |
Physics |
4165299436 |
January 10 |
Shift 1 |
Chemistry |
4165299357 |
January 10 |
Shift 1 |
Chemistry |
4165299447 |
January 10 |
Shift 1 |
Mathematics |
4165299387 |
January 10 |
Shift 1 |
Mathematics |
4165299477 |
January 10 |
Shift 2 |
Physics |
41652910414 |
January 10 |
Shift 2 |
Physics |
41652910504 |
January 11 |
Shift 1 |
Physics |
4165299150 |
January 11 |
Shift 1 |
Physics |
4165299240 |
January 11 |
Shift 2 |
Mathematics |
4165299566 |
January 11 |
Shift 2 |
Physics |
4165299525 |
January 11 |
Shift 2 |
Mathematics |
4165299656 |
January 11 |
Shift 2 |
Physics |
4165299615 |
January 12 |
Shift 1 |
Chemistry |
4165299736 |
January 12 |
Shift 1 |
Chemistry |
4165299826 |
January 12 |
Shift 2 |
Physics |
4165299874 |
January 12 |
Shift 2 |
Physics |
4165299882 |
January 12 |
Shift 2 |
Physics |
4165299964 |
January 12 |
Shift 2 |
Physics |
4165299972 |
JEE Main 2019 results for Paper 1 were declared on January 19. NTA score for JEE Main 2019 Paper-II will be declared later. Please note that JEE Main 2019 All India Ranks (AIR) will be announced once the April session of the exam ends. The ranks will be published taking into consideration better of the two NTA Scores of all candidates who have appeared in January and April session of the examinations.
Also read:
- How To Calculate JEE Main 2019 Rank From Percentile
- JEE Main 2019 Topper Interview (January Exam): Dhruv Arora from Indore secures 100 percentile
- JEE Main 2019 Toppers (Paper 1) - 15 Students Secure 100 Percentile
- JEE Main 2019 Paper 1 Analysis, Expected Cutoff & Student Reaction
- How To Calculate JEE Main 2019 Marks using Official Answer Keys
This is a collection of news and articles on various topics ranging from course selection to college selection tips, exam preparation strategy to course comparison and more. The topics are from various streams inclu... Read Full Bio
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Student Forum
Answered Yesterday
Yes, it is very easy to get into AOT with a rank of 12k for the Computer Science and Engineering through JEE Main exam. The institute offers B.Tech courses under five specializations. Talking about the cutoff, the AOT cuoff 2024 for the BTech courses has been ranged between 45106 and 996423 for the
A
Beginner-Level 4
Answered 2 days ago
Hey dude,
I consider low percentile as 75%. With this u cant get IIT, NIT, or other gift universities utill u are in st category.
However You can get good universities with low JEE percentile. Some college or universities consider JEE percentile as part of their admissions. For example, My college sa
Answered 2 days ago
Hey Azfar,
I wrote JEE advance twice after 12th. Based on my experience, I share this,
if the candidate does not attempt JEE Advanced in the same year that he or she qualifies his Class 12 examinations, then that candidate will have no two attempts left. In the eligibility criteria, candidates are a
Answered 2 days ago
Hi bobika,
I wrote both JEE and neet. so with my experience, Let me give you this details:
NEET Eligibility
The age of the candidate must be 17 years as of December 31 of the admission year. Candidates must have completed 10+2 with Physics, Chemistry, Biology/Biotechnology, and English as core subject
Answered 3 days ago
The candidate must at least score a minimum of 50% marks in their examination. NIT Rourkela offers admission after considering the 12th exam results, JEE Main score. A merit list shall be made category-wise, listing the All India Rank (AIR) of candidates which is used for the Counselling process.
To
Answered 3 days ago
The JEE Main 2025 Session 1 exam for Raj Kumar Goel Institute of Technology (RKGIT) is scheduled to be held between January 22 and January 29, 2025. The exam for BArch and BPlan courses will be conducted on January 30, 2025.
Raj Kumar Goel Institute of Technology is a private college in Ghaziabad,
R
Contributor-Level 8
Answered 3 days ago
Here are some JEE Main cutoff ranks for Raj Kumar Goel Institute of Technology (RKGIT) in Ghaziabad, Uttar Pradesh:
B.Tech. in Information Technology: In 2024, the cutoff ranks for the rounds were 604,428 for round 1, 758,104 for round 2, 793,619 for round 3, and 963,560 for round 4.
B.Tech. in Co
R
Contributor-Level 8
Answered 4 days ago
Candidates who aspire to take admission to Amrita Vishwa Vidyapeetham Chennai BTech courses can apply via JEE Main scores. As per official sources, the JEE Main tentative dates for sessions 1 and 2 have been announced by the NTA. As per the announcement, the session 1 exam is tentatively scheduled t
S
Contributor-Level 10
Answered 4 days ago
Since you're in Class 11, it's the perfect time to begin your preparation for JEE Mains and Advanced. Here's a list of best books for Mathematics, Physics, and Chemistry that will guide you through both the fundamentals and advanced concepts:
- NCERT Books:
- IIT Mathematics by M.L. Khanna
- Problems in Calc
Y
Beginner-Level 4
Answered 4 days ago
Yes, admissions to the Amrita School of Engineering Chennai BTech programme can be taken even without having a valid JEE Main score. The university organises an in-house entrance test, namely AEEE. The exam takes place twice annually. The first phase is conducted in the month of February. Interested
S
Contributor-Level 10
Can I get AOT with 12k cutoff for Computer Science and Engineering through JEE Main?