M.Tech. in Information Technology
- Public/Government Institute
- Estd. 1960
M.Tech. in Information Technology at NIT Surathkal Overview
Duration | 2 years |
Course Level | PG Degree |
Mode of Course | Full Time |
Total Tuition Fees | ₹3.21 Lakh |
Average package | ₹ 12.64 Lakh |
Official Website | Go to Website |
Seat breakup | 33 |
Type of University | Public/Government |
M.Tech. in Information Technology at NIT Surathkal Fees
Fee components | Amount (2 years) |
---|---|
Tuition fee is calculated on the basis of 1st semester. Actual amount may vary.
The fees might include components other than tuition fees. | ₹ 3.21 Lakh |
Hostel fee mentioned above is for cheapest option available. For other options available, please refer to fee pdf.
The fees might include components other than hostel fees.
Meal Plan is included in me Hostel fee mentioned above is for cheapest option available. For other options available, please refer to fee pdf.
The fees might include components other than hostel fees.
Meal Plan is included in mentioned fee. | ₹ 32,000 |
One-time Payment includes Admission Fee, Security Deposit and Convocation Fee. | ₹ 9,270 |
₹ 3.62 Lakh |
These are based on information available on various sources. Latest values may differ.
M.Tech. in Information Technology at NIT Surathkal Curriculum
Latest curriculum for M.Tech. in Information Technology at NIT Surathkal can be downloaded from the below link. The curriculum PDF has semester wise course structure, electives and detailed course content. You can also check course curriculum of other specializations offered in M.E./M.Tech at NIT Surathkal
M.Tech. in Information Technology at NIT Surathkal Placements
Particulars | Statistics (2023) |
---|---|
Average Salary | INR 12.64 Lakh |
Highest Salary | INR 38.14 Lakh |
Median Salary | INR 11.00 Lakh |
% Batch placed | 83.05 |
M.Tech. in Information Technology at NIT Surathkal Frequently Asked Questions
Q: What is the eligibility criteria for M.Tech course at NIT Surathkal?
The eligibility criteria for MTech course at the NIT Surathkal is that candidate should have passed BTech with a minimum of 60% aggregate from a recognised university. Aspirant should have the degree and mark sheets (original/copies) at the time of form filling and admission confirmation. These documents are required for verification purposes. Further, the selection process include GATE + CCMT Counselling.
Q: How to get into NIT Surathkal for MTech?
Candidates seeking admission shall apply for GATE through the COAPS portal and take the entrance exam. Candidates with a Bachelor’s or an equivalent degree in an appropriate branch of Engineering of a minimum four-year duration with 60% aggregate (55% for SC/ST/PwD) can apply. The students shortlisted based on GATE score are further required to appear for CCMT counselling following which the seat allotment is carried out.
Q: Is there any interview conducted for M.Tech course admission at NIT Surathkal?
No, the admission is purely granted based on GATE scores and performance in CCMT counselling. Candidates who score marks greater than or equal to the cutoff marks become eligible to take part in the counselling. There is no other selection round.
Q: Can I get into NIT Surathkal for CSE with a GATE score of 741 in the general category?
NIT Surathkal GATE Cutoff 2024 has been released for Round 1. The most competitive course was M.Tech in CSE. The Cutoff score for CSE stood at 742, for the General AI category candidates. Therefore, candidate with the Cutoff score of 741 cannot get CSE at NIT Surathkal. However, Cutoff score of 741 can be considered for various other courses such as M.Tech in IT, M.Tech in VLSI Design, etc.
For the OBC AI category candidates, the Cutoff score for CSE closed at 701. Candidates can refer to the table provided in this section to view the NIT Surathkal M.Tech Cutoff scores for different categories.
Q: How to get admission for M.Tech at NIT Surathkal?
NITK Surathkal admits students through CCMT for all the M.Tech programmes. For all guidelines, the prospective candidates are advised to carefully read the information brochure and various other documents which will be available in CCMT website. Admission to a MTech. Programme is open to candidates who have passed the prescribed qualifying examination, with a Cumulative Grade Point Average (CGPA) of at least 6.5 in the 0-10 scale grading system, or not less than 60% marks in the aggregate
M.Tech. in Information Technology at NIT Surathkal Entry Requirements
M.Tech. in Information Technology at NIT Surathkal Admission Process
Important Dates
M.Tech. in Information Technology at NIT Surathkal Cutoffs
CCMT round-wise cutoff Rank: (General-All India)
Round | 2024 |
---|---|
1 | 694 |
2 | 672 |
3 | 664 |
4 | 624 |
5 | 617 |
6 | 602 |
GATE round-wise cutoff Rank: (General-All India)
Round | 2020 | 2023 |
---|---|---|
1 | 721 | - |
2 | 692 | - |
3 | 671 | - |
4 | 616 | - |
5 | 608 | - |
6 | - | 543 |
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M.Tech. in Information Technology at NIT Surathkal Students Ratings & Reviews
- 4-51
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Q: How much percentile is required for NIT Surathkal?
National Institute of Technology Karnataka course admissions is based on the entrance exam. Candidates who want admission must first meet the basic criteria for eligibility and then take the entrance exam. NIT Surathkal BTech admissions are based on JEE Main scores, followed by JoSAA counselling. Candidates must secure a 75% or above percentile to get admission to BTech courses offered by NIT Surathkal. For candidates to qualify for admission in the IITs/NITS/IIITs and such other CFTIs whose admission is based on JEE ranks, they should have secured at least 75% aggregate in Class 12, or be in the top 20 percentile in the Class 12 exam conducted by the respective Boards (65% for SC/ST/PwD students)
Q: How many seat seats are available for BTech at NIT Surathkal?
The BTech specialisations along with the seat intake offered are tabulated below:
BTech Specialisation | Seat Intake (State) | Seat Intake (All India Seats) |
---|---|---|
Chemical Engineering | 29 | 29 |
Civil Engineering | 57 | 58 |
Computational and Data Science | 15 | 15 |
Computer Science Engineering | 58 | 57 |
Electronics and Communication Engineering | 58 | 58 |
Mechanical Engineering | 87 | 87 |
Metallurgical and Materials Engineering | 29 | 29 |
Mining Engineering | 29 | 29 |
Q: What to do after JEE Main session 2 result?
Candidates preparing for IITs are only required to appear for the JEE Advanced entrance exam after qualifying JEE Main. Students who who secure above the 98th percentile in JEE Main 2024 Session 2 should start preparing for JEE Advanced 2025 immediately. Those who score between 95th and 98th percentile should focus on improving their JEE Main score by taking multiple mock tests and practicing previous year's question papers. By analysing their strengths and weaknesses, candidates can identify their areas of proficiency and topics where they need improvement. If they can achieve full marks in their practice sessions, they can start preparing for JEE Advanced. However, if they cannot score full marks, it is recommended that they appear for multiple mock test series for more practice.
Q: Can I join NIT Surathakal through KCET?
No, admissions at NIT Surathkal are only through national-level entrance exams, such as JEE Mains, GATE, CAT etc. Apart from this, students need to meet the last educational qualification s per course requirement. Studnets can check the list of course eligibility and selection for few of top courses offered at NIT Surathakal admissions from the table presneted below:
Courses | Eligibility | Selection Criteria |
---|---|---|
MCA | Graduate with 60% aggregate | NIMCET + Counselling |
BTech | Class 12 with 75% aggregate | JEE Main, DASA UG, CSAB + JoSAA counselling |
MBA | Graduation with 50% aggregate | MAT, CAT, GATE + GD & PI |
MSc | Graduation with 60% aggregate | IIT JAM, +CCMN counselling |
MTech | Graduation with 60% aggregate | GATE + CCMT counselling |
Other than the entrance exam scores there is no other means to get into NIT Surathakal
Q: What is the expected JEE Main cutoff 2024?
NIT Manipur JEE Main cutoff 2024 has been released for admission to the BTech courses. During the Round 1 cutoff, the closing rank for CSE was 25886 for the General category students under the AII India Quota. Among OBC candidates, the closing rank for B.Tech. in Computer Science and Engineering stood at 8750. Candidates seeking admisison to NIT Manipur can refer to the table below to check out the Round 1 closing ranks for BTech in CSE course for various categories under the AI quota:
Category | JEE Main 2024 Expected Cutoff |
---|---|
Common Rank List | 90-91 |
Gen-EWS | 75-76 |
OBC-NCL | 73-74 |
SC | 51-52 |
ST | 37-38 |
PwD | 0.0013527 |
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