Derivation of Escape Velocity: Overview, Questions, Preparation

Motion 2021 ( Motion )

Updated on Jun 23, 2021 01:10 IST

What is Escape Velocity?

It is one of the most common topics of kinematics in physics. Escape velocity is used to calculate the minimum speed of an object through gravitational pull on the non-propelled object. It makes it reach an infinite distance from the object.

The formula of escape velocity is:

Ve= √ 2GM /r

 Here, Escape Velocity is denoted as Ve.

The gravitational constant is denoted as G.

Mass is denoted as M.

We denote the distance from the object as r

The escape velocity of the Earth

The escape velocity of the earth is 40,270 km approximately, which is equal to 11,186 m/s.

 The acceleration due to gravity from the earth is g = 9.8 m/s2

Radius is 6.4 x 106 m

Escape velocity is Ve = √2 × 9.8 × 6.4 × 106

That is why Ve  = 11.2 x 103 m/s = 11.2 km/s

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Derivation of Potential and kinetic energy

The formula of initial potential energy is:

PEi = GMm / Ri

Here, M is the mass of escaping body

m is the mass of attracting body

G is the gravitational constant

Ri is the separation between the bodies

The formula of initial kinetic energy is

KE = ½ mve 2

Here, M is the mass of the object.

Ve is the initial velocity or escape velocity.

Now, the sum of kinetic and potential energy will give us:

TEi = KEi + PEi

TEi. = mve / 2 - GMm / Ri

Escape velocity Derivation

Now, TEi = TE

KEi + PEi = 0

After substituting the values, we will get,

mve / 2 - GMm / Ri = 0

Let us now add both the sides by GMm / Ri

Now, we have ve2 = 2GM / Ri

Now, apply square root on both sides.

Ve = +- √ (2GM / ri)

The gravitational convention is far away from the other object so that the escape velocity will be negative, and we will get out a final formula which is as follows:

Ve = - √ (2GM / ri)

Derivation of Escape velocity for Class 11

The chapter 'Introduction to Motion' holds a weightage of 6 marks. It includes 3 questions in total. These 3 questions consist of one objective type question of 1 mark, one very short question of 2 marks, and one short question of 3 marks bringing a total up to 6 marks.

Illustrated Examples

Example 1) Illustrates the formula of escape velocity.

Answer – the formula of escape velocity is Ve = - √ (2GM / RI)

Example 2) State the formula of initial potential energy.

Answer – the formula of initial potential energy is PEi = GMm / Ri

Example 3) Illustrate the formula of initial kinetic energy.

Answer – the formula of initial kinetic energy is KE = ½ mve 2

FAQs on Escape Velocity

Question 1) What do you mean by escape velocity?

Answer - Escape velocity is used to calculate an object’s minimum speed through gravitational pull on the non-propelled object.

Question 2) what is the escape velocity of the sun, moon, and earth in km/s?

Answer – the escape velocity of the sun, moon, and the earth is as follows:
  • The escape velocity of the moon is 2.38 km/s
  • The escape velocity of the sun is 618 km/s
  • The escape velocity of the earth is 11.2 km/s

Question 3) write the difference between escape velocity and orbital velocity.

Answer – The basic difference between the escape and orbital velocity is that orbital velocity is the speed required to reach the orbit’s centre. In contrast, escape velocity is the speed required to leave or escape the orbit.

Question 4) On what escape velocity is dependent on?

Answer – The escape velocity is dependent on the celestial body.

Question 5) What is the escape velocity of Jupiter?

Answer – The escape velocity of Jupiter is 59.5 km/s.
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