B.Tech. in Mechanical Engineering
- Public/Government Institute
- Estd. 1960
B.Tech. in Mechanical Engineering at NIT Surathkal Overview
Duration | 4 years |
Course Level | UG Degree |
Mode of Course | Full Time |
Total Tuition Fees | ₹5.00 Lakh |
Average package | ₹18.26 Lakh |
Official Website | Go to Website |
Seat breakup | 174 |
Type of University | Public/Government |
B.Tech. in Mechanical Engineering at NIT Surathkal Fees
Fee components | Amount (4 years) |
---|---|
Fee is calculated on the basis of 1st year. Actual amount may vary. For Self Financed fee structure, kindly refer Fee PDF. | ₹ 5.00 Lakh |
The fees might include components other than hostel fees.
Meal Plan is not included in mentioned fee | ₹ 67,200 |
One time fee includes Caution Deposit. | ₹ 6,390 |
₹ 5.74 Lakh |
These are based on information available on various sources. Latest values may differ.
B.Tech. in Mechanical Engineering at NIT Surathkal Curriculum
Latest curriculum for B.Tech. in Mechanical Engineering at NIT Surathkal can be downloaded from the below link. The curriculum PDF has semester wise course structure, electives and detailed course content. You can also check course curriculum of other specializations offered in B.E. / B.Tech at NIT Surathkal
B.Tech. in Mechanical Engineering at NIT Surathkal Placements
Particulars | Statistics (2023) |
---|---|
Average Salary | INR 18.26 Lakh |
Highest Salary | INR 54.75 Lakh |
Median Salary | INR 15.00 Lakh |
Lowest Salary | INR 4.50 Lakh |
% Batch placed | 93 |
B.Tech. in Mechanical Engineering at NIT Surathkal Frequently Asked Questions
Q: What is the fee structure for BTech programme at NIT Surathkal?
The total course fee for the BTech programme at NIT Surathkal is INR 5 lakh. The duration of the course is for four years. Moreover, the eligibility for NIT Surathkal BTech admissions is that candidate should have passed Class 12 with a minimum of 75% aggregate. The entrance exams accepted include JEE Main and DASA UG. Eligible candidates can apply by visiting the official website.
Q: What has been the trend for cut-off in BTech in Mechanical Engineering at NIT Surathkal in the last few years?
The cutoff trend for BTech at NIT Surathkal - National Institute of Technology has been increasing in the recent years. In 2021, the closing rank for BTech under the General category for all India quota was 13365. In 2022, it increased to 13567. Likewise, the cut off ranks have changed from 21629 to 25794 for OBC, 2472 to 65567 for SC, 79634 to 62185 for ST, 17978 to 18151 for EWS and 586 to 353872 for PWD. This trend is likely to continue in the coming years, as the demand for engineering education in India continues to grow. Similar cut off trend can be seen for female candidates under all categories however the ranks are slightly different.
Q: What is the BTech admission procedure at NIT Surathkal?
NIT Surathkal BTech admission is done basis JEE Main score followed by JoSAA counseling. Candidates need to apply online for NIT Surathkal admissions. The documents required at the time of admission include Photo ID proof (Government authorised), Class 10 passing out certificate (date of birth proof), Transfer certificate, Character certificate, Migration Certificate, Medical Certificate, etc.
Q: What are the popular BTech streams at NIT Surathkal?
According to the placement data and student reviews from various sources, the most popular BTech streams at NIT Surathkal are Computer Science and IT. NITK Surathkal provides undergraduate, postgraduate, and doctoral-level programmes in Engineering, Technology, Science, and Management. The technology institute has 15 departments and offers 20+ courses. For admissions to these courses, candidates need to fulfil the eligibility criteria and clear the entrance exam.
Q: Can I get admission at NIT Surathkal in BTech CSE if my rank is between 23000 and 24000?
NIT Surathkal JEE Main Round 6 cutoff for Civil Engineering is 23632 which is very close to this range. This was for general category under All India quota. Unless the candidate belongs to some other category or domicile, one can not afford to score less than this. With this rank, there is a probability of getting admission however since, the cut offs keep changing from round to round, better ranks definitely increases your chances of getting admission in NIT Surathkal.
B.Tech. in Mechanical Engineering at NIT Surathkal Entry Requirements
B.Tech. in Mechanical Engineering at NIT Surathkal Admission Process
- CounsellingAdmissions is through counseling based on the rank obtained in JEE mains for Indian nationals Admission is on the basis of merit in SAT through DASA scheme for Foreign nationals/Persons of Indian Origin/ Non-Resident Indians/Overseas Citizens
B.Tech. in Mechanical Engineering at NIT Surathkal Cutoffs
JEE Main round-wise cutoff Rank: (General-All India)
Round | 2022 | 2023 | 2024 |
---|---|---|---|
1 | 10840 | 11214 | 10488 |
2 | 11407 | 12610 | 10643 |
3 | 11596 | 12610 | 10643 |
4 | 11596 | 12610 | 10643 |
5 | 11596 | 12610 | 12380 |
6 | 12255 | 14069 | 14333 |
7 | 13520 | 15059 | 14571 |
8 | 13567 | 15193 | - |
DASA UG round-wise cutoff Rank: (General-All India)
Round | 2020 | 2021 | 2022 |
---|---|---|---|
1 | 757 | 986 | 644 |
2 | - | 986 | 644 |
3 | - | 986 | 644 |
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Q: How many entrance exam cutoffs will be released for admission to BTech at NIT Surathkal?
NIT Surathkal will release 7-8 rounds of JEE Main cutoffs for admission to BTech. The cutoffs will be released on a rolling basis, and the seats will be filled on a first-come, first-served basis. The cutoffs will be based on the following factors:
- The JEE Main score of the candidate
- The category of the candidate
- The number of seats available in the course
Candidates must visit the official website of entrance exam to read clear instructions on how to proceed with the counselling process, once the round is released.
Q: How much percentile is required for NIT Surathkal?
National Institute of Technology Karnataka course admissions is based on the entrance exam. Candidates who want admission must first meet the basic criteria for eligibility and then take the entrance exam. NIT Surathkal BTech admissions are based on JEE Main scores, followed by JoSAA counselling. Candidates must secure a 75% or above percentile to get admission to BTech courses offered by NIT Surathkal. For candidates to qualify for admission in the IITs/NITS/IIITs and such other CFTIs whose admission is based on JEE ranks, they should have secured at least 75% aggregate in Class 12, or be in the top 20 percentile in the Class 12 exam conducted by the respective Boards (65% for SC/ST/PwD students)
Q: What to do after JEE Main session 2 result?
Candidates preparing for IITs are only required to appear for the JEE Advanced entrance exam after qualifying JEE Main. Students who who secure above the 98th percentile in JEE Main 2024 Session 2 should start preparing for JEE Advanced 2025 immediately. Those who score between 95th and 98th percentile should focus on improving their JEE Main score by taking multiple mock tests and practicing previous year's question papers. By analysing their strengths and weaknesses, candidates can identify their areas of proficiency and topics where they need improvement. If they can achieve full marks in their practice sessions, they can start preparing for JEE Advanced. However, if they cannot score full marks, it is recommended that they appear for multiple mock test series for more practice.
Q: How to apply for MSc in NIT Surathkal?
The candidates taking admission to MSc courses need to complete the application process of IIT-JAM by visiting its official website (jam.iitr.ac.in). Candidates selected further need to register for CCMN counselling as well through its website (ccmn.admissions.nic.in). The aspirants must check the eligibility requirements before taking the exam.
Q: What are the cut off marks for NIT Surathkal?
NIT Surathkal cutoff 2024 for has been concluded after the release of Round 7 for the admission for BTech courses in the form of opening and closing ranks. The Last Round rank for NIT Surathkal JEE Main cutoff 2024 ranged from 1920 to 30509 for the General AI category, wherein, the most competitive course is B.Tech.6 in Computer Science and Engineering with Last Round score of 1920.
Similarly, for the OBC AI category, the cutoff ranged between 3282 and 38271, wherein, the most competitive course was BTech in Computer Science and Engineering. Comparing it with the previous years' cutoff, it is observed that there is a fluctuating trend in the cutoffs for the General AI category. Candidates seeking admission to NIT Rourkela can refer to the table given below to check out the JEE Main closing cut off 2024 for General AI category:
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