JEE Main Marks vs Percentile vs Rank 2025: Calculate Percentile and Rank Using Marks
Joint Entrance Exam (JEE) Main 2025 ( JEE Main )
Registration - 1 Feb '25 - 25 Feb '25
Check your JEE Main 2025 marks vs percentile and marks vs rank in the JEE Mains exam. In this article, you'll learn to check the JEE Main marks vs rank 2025 formulas to analyze the rank based on scores obtained in the JEE Main 2025 exam. Candidates can calculate their JEE Main 2025 percentile score using the formula used by NTA. JEE Mains percentile can also be used to know the expected rank before the JEE Main result 2025 is announced.
JEE Mains Marks vs Percentile vs Ranks 2025: Students often have doubts related to marks vs percentile in JEE Mains. Candidates are provided here with a detailed analysis of marks vs percentile in JEE Main to help estimate their most probable marks easily. Candidates are also provided here JEE Main marks vs percentile vs rank to help them understand their rank in the exam. It is to be noted here that the jee mains marks vs percentile vs rank is just to calculate the probable rank in the exam.
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There is a 90% more chance of getting best college recommendations by sharing preferences.The National Testing Agency (NTA) will release the JEE Main 2025 results as percentile scores. The JEE Main percentile scores are not the actual marks but the normalized marks of candidates. Normalization removes any possible parity in the difficulty level of the JEE Mains 2025 question paper as the exam is held in several shifts and days. Also, the comparative analysis of marks vs rank JEE Mains can be seen on this page.
NTA has clearly explained the normalization process for calculating the JEE Main percentile score. The raw marks obtained in JEE Main 2025 by any candidate are converted to a percentile score for preparing the result. The actual percentile and rank will be mentioned in JEE Main 2025 result.
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JEE Main Expected Marks vs Percentile 2025
The expected marks vs percentile for JEE Mains 2025 are available here. Candidates can refer to the table below for marks vs percentile in JEE Mains 2025 to get an idea of their approximate percentile range in JEE Main result.
| JEE Main 2025 Score | JEE Main 2025 Percentile |
|---|---|
| 300-281 | 100 - 99.99989145 |
| 271 - 280 | 99.994681 - 99.997394 |
| 263 - 270 | 99.990990 - 99.994029 |
| 250 - 262 | 99.977205 - 99.988819 |
| 241 - 250 | 99.960163 - 99.975034 |
| 231 - 240 | 99.934980 - 99.956364 |
| 221 - 230 | 99.901113 - 99.928901 |
| 211 - 220 | 99.851616 - 99.893732 |
| 201 - 210 | 99.795063 - 99.845212 |
| 191 - 200 | 99.710831 - 99.782472 |
| 181 - 190 | 99.597399 - 99.688579 |
| 171 - 180 | 99.456939 - 99.573193 |
| 161 - 170 | 99.272084 - 99.431214 |
| 151 - 160 | 99.028614 - 99.239737 |
| 141 - 150 | 98.732389 - 98.990296 |
| 131 - 140 | 98.317414 - 98.666935 |
| 121 - 130 | 97.811260 - 98.254132 |
| 111 - 120 | 97.142937 - 97.685672 |
| 101 - 110 | 96.204550 - 96.978272 |
| 91 - 100 | 94.998594 - 96.064850 |
| 81 - 90 | 93.471231 - 94.749479 |
| 71 - 80 | 91.072128 - 93.152971 |
| 61 - 70 | 87.512225 - 90.702200 |
| 51 - 60 | 82.016062 - 86.907944 |
| 41 - 50 | 73.287808 - 80.982153 |
| 31 - 40 | 58.151490 - 71.302052 |
| 21 - 30 | 37.694529 - 56.569310 |
| 20 - 11 | 13.495849 - 33.229128 |
| 0 - 10 | 0.8435177 - 9.6954066 |
NTA score in JEE Mains is the aggregate percentile score of all three subjects. Candidates having query what is NTA score are informed that NTA score is same as aggregate percentile score. Candidates can check below NTA score meaning and qualifying marks for JEE Mains 2025. Read more below to know how to calculate percentile in JEE and NTA score vs Percentile.
Q: Is 75 percent marks in class 12 required for JEE Mains?
Q: What is the expected NIT Calicut JEE Main cutoff 2024?
Going as per the past three year trends candidates can expect the closing ranks for NIT Calicut JEE Main cutoff 2024 Round 1 Seat Allotment for top specialisations between the following range:
- B.Tech. in Computer Science and Engineering must range between 2717 and 4455
- B.Tech. in Electrical and Electronics Engineering must range between 10612 and 12119
- B.Tech. in Electronics and Communication Engineering must range between 7127 and 7563
- Bachelor of Architecture (B.Arch.) must range between 269 and 316
- B.Tech. in Engineering Physics must range between 16153 and 16430
Q: What is NIT Rourkela cutoff for BTech?
NIT Rourkela cutoff 2024 has been released across various specialisations in opening and closing ranks. NIT Rourkela BTech cutoff 2024 ranged between 2680 and 35593 for the General AI category candidates, wherein BTech in CSE is the most competitive course. The easiest BTech specialisation to secure admission in is B.Tech. in Ceramic Engineering + M.Tech. in Industrial Ceramic Engineering. For a detailed NIT Rourkela branch-wise cutoff 2024, candidates can refer to the table below for the Round 1 cutoff. The cutoff mentioned below is for the General category under the AI Quota.
| JEE Main 2025 Result | JEE Main 2025 Cutoff |
| JEE Main 2025 Answer Key | JEE Main Previous Year Question Paper PDF |
Use your JEE Main 2025 Percentile and predict your Rank and the Colleges you are eligible for using Shiksha's JEE Main Rank and College Predictor. Get cut-off information for 600 colleges and 2500 colleges
Predict JEE Main CollegesJEE Mains 2025 Expected Cutoff
| Category |
Expected JEE Main 2025 Cutoff |
| CRL |
100.0000000 to 92.3362181 |
| OBC-All |
92.2312696 to 79.6457881 |
| SC-All |
92.2312696 to 62.0923182 |
| ST-All |
92.2312696 to 47.6975840 |
| UR-PwD |
92.2041331 to 0.0015700 |
Why JEE Main Result is announced in Percentile?
The JEE Main 2025 exam will be conducted in two sessions in January and April over 5 days with 2 shifts each day. There's a possibility that the question paper for a particular day can be more difficult or easier than any other day. To overcome this possible parity in difficulty level, normalization is done. The normalized marks are not the actual marks obtained by the candidate but a comparative score obtained using a specially developed formula by NTA. The range of JEE Mains marks vs percentile is given below based on the previous years' trends and the normalization formula used by NTA. The article below will provide important details to candidates about JEE Main marks vs percentile.
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What is JEE Main 2025 Percentile Score?
The JEE percentile score compares an applicant's performance to all other test takers and is not the same as a percentage score or raw marks. The JEE Main percentile score indicates the percentage of candidates who scored lower or equal to a particular score in the examination. Knowing how to access an estimated rank before the official announcement can be beneficial, but only if the applicant understands the normalization process and tiebreakers used to determine JEE Main marks and percentiles.
Also Read: Top Engineering Colleges in India other than IIT, NIT and IIIT
JEE Main 2025 Percentile vs Ranks
The release of percentile and rank statistics is dependent on various factors such as the number of registered candidates, the number of questions on the exam, the difficulty level of the exam, and trends from previous years' marks and ranks in JEE Main.
Q: How much is 120 marks in JEE Mains percentile?
The National Testing Agency (NTA) will declare the JEE Mains result 2025 in the form of percentile scores. Candidates can check here the JEE Main 2025 marks vs percentile data to understand the 120 marks in JEE Main percentile.
As per the last year JEE Main marks vs percentile analysis, 120 marks would be around 95 to 97 percentile. However, the exact JEE Main 2025 percentile marks 120 would vary depending upon the highest number scored by the candidate in a particula shift and the total number candidates appeared in that particular shift. More details about JEE Main marks vs percentile vs rank can be checked to understand in details.
Q: How to calculate percentile in JEE?
NTA uses a formula to calculate NTA score in JEE Main. The formula used is
Q: What is the cutoff for BTech at NIT Andhra Pradesh for OBC category?
NIT Andhra Pradesh BTech cutoff 2024 for BTech courses ranged between 25704 and 91199 for OBC category. Wherein, the most competitive course was BTech in Computer Science and Engineering and the least competitive course was BTech in Biotechnology. While the admissions are based on the scores/rank obtained in JEE Main, the last cutoffs also change a lot depending on All India quota or Home State. It also varies if the applicant is a female.
Q: Can I get NIT with 95 percentile in JEE Main?
It is possible for you to secure a seat in an NIT (National Institute of Technology), although it may not guarantee your preferred branch or institute. If your percentile is above 96, your chances of getting into a respectable NIT increases, but you may need to compromise on your branch selection. However, if you aim for a decent NIT with a preferred branch in the core field, you would need to score above 97.5%. On the other hand, if your goal is to get admission to a top college with the CSE (Computer Science and Engineering) branch, your score would need to be higher than 99.4%.
Q: Is the NTA percentile score and percentage same?
The percentile vs rank statistics for JEE Main 2025 is provided here. Candidates can check here percentile vs rank data. Candidates can refer to the table below for the same:
| JEE Main 2025 Percentile | JEE Main 2025 Rank |
|---|---|
| 100 - 99.99989145 | 1 - 20 |
| 99.994681 - 99.997394 | 80 - 24 |
| 99.990990 - 99.994029 | 83 - 55 |
| 99.977205 - 99.988819 | 210 - 85 |
| 99.960163 - 99.975034 | 367 - 215 |
| 99.934980 - 99.956364 | 599 - 375 |
| 99.901113 - 99.928901 | 911 - 610 |
| 99.851616 - 99.893732 | 1367 - 920 |
| 99.795063 - 99.845212 | 1888 - 1375 |
| 99.710831 - 99.782472 | 2664 - 1900 |
| 99.597399 - 99.688579 | 3710 - 2700 |
| 99.456939 - 99.573193 | 5003- 3800 |
| 99.272084 - 99.431214 | 6706 - 5100 |
| 99.028614 - 99.239737 | 8949 - 6800 |
| 98.732389 - 98.990296 | 11678 - 9000 |
| 98.317414 - 98.666935 | 15501 - 11800 |
| 97.811260 - 98.254132 | 20164 - 15700 |
| 97.142937 - 97.685672 | 26321 - 20500 |
| 96.204550 - 96.978272 | 34966 - 26500 |
| 94.998594 - 96.064850 | 46076 - 35000 |
| 93.471231 - 94.749479 | 60147 - 46500 |
| 91.072128 - 93.152971 | 82249 - 61000 |
| 87.512225 - 90.702200 | 115045 - 83000 |
| 82.016062 - 86.907944 | 165679 - 117000 |
| 73.287808 - 80.982153 | 246089 - 166000 |
| 58.151490 - 71.302052 | 385534 - 264383 |
JEE Main Normalisation Formula
After compiling the raw marks, the NTA applies the normalization formula to get the percentile scores of a candidate for each subject – Maths, Physics, and Chemistry as well as the total. The highest score of each session will get the same percentile of 100 which is ideal. The percentile score has been used to prepare the JEE Main merit list. The percentile scores will be calculated up to 7 decimal places to avoid ties among candidates with the same scores.
The JEE Main percentile score obtained by a candidate is determined only after applying normalization to the marks obtained by a candidate. JEE Main Percentile scores indicate the percentage of candidates who have scored equal to or below that particular percentile in the examination. A percentile score is measured on a scale of 100 to 0 for each session of examinees. The formula to calculate JEE Mains marks vs percentile is
JEE Main 2025 Normalisation Process: Tie Breaker Guidelines
The following rule comes into effect when two or more candidates obtain equal percentile scores. The inter-se merit will be determined according to the following rules in case of a tie.
Candidates obtaining a higher Percentile Score in Mathematics will be ranked higher
- If a tie still exists, the candidate with a higher Percentile Score in Physics will be given a higher rank
- If a tie still exists, the candidate obtaining a higher Percentile Score in Chemistry will get a higher rank
- If a tie still exists, candidates older in age will be given a preference
The JEE Main result is released separately for each session. The best scores of the two sessions are considered for candidates who appeared in both sessions. The merit list is prepared on the final scores and ranks are announced based on the same.
Read More:
How to calculate JEE Main 2025 Percentile Score - Know Normalization Process
How to Calculate JEE Main 2025 Rank From Percentile
JEE Main Marks vs Percentile vs Rank 2025 FAQs
Q. When will JEE Main 2025 Result be declared?
A. The JEE Main 2025 session 1 results will be announced by February 12. Candidates can check the result from the official website jeemain.nta.nic.in by login to the website using their application number and date of birth.
Q. I got 281 marks in JEE Main. What will be my Percentile?
A. . It is 99.96 percentile, it's a really good performance and you should be able to get under AIR 100. Any score above 250 in JEE Main is considered a good score. To score well in JEE Main, candidates must have a good understanding of Class 11 and Class 12 Physics, Chemistry and Mathematics.
Q. If someone gets 23.072 percentile, what will be the score in JEE Main?
A. Around 15-20 marks out of 300.
Q. How much percentile is required for NIT?
A. General Category candidates need to score a minimum of 95 percentile score to get NITs. For reserved category candidates, an 80 percentile score is enough to get NITs.
Q. What is a good score in JEE Main?
A. 250 marks in JEE Main can be considered as a good score. The candidates scoring above 250 will get a percentile between 85 -95. A high score in JEE Main is required to get admission in NITs and to appear for JEE Advanced. The top scores in JEE Advanced are given admission in IITs.
Q. What is needed to score good marks in JEE Main?
A. To score good marks in JEE Main exam it is very important for candidates to have a good under-standing of Physics, Chemistry, and Mathematics. The basics should be strong. The questions are mostly asked from Class 11 and Class 12 curriculum. The candidates must understand the concept behind every topic to use the right formula to solve the questions in JEE Main 2025.
Q. How JEE Main rank is prepared?
A. JEE Main rank is prepared by compositing the scores of JEE Main and marks of class XII in the ratio of 60:40. According to it, the scores are arranged in merit.
Q. My CBSE percentage is 75.5. Am I eligible for JEE Main 2025?
A. Yes, you are eligible to appear for JEE Main.
Q. Is 45 percentile enough for JEE Mains?
A. Candidates can appear in JEE Main irrespective of their percentage in class 12. The requirement of percentage is for admission in the institute not for appearing in JEE Mains.
Q. If I appear in all the sessions. Which scores will be counted while declaring the result?
A. The best of the scores from all the sessions will be considered for merit/ranking in JEE Main 2025.
Satyendra is an expert news writer and content editor at shiksha.com with over ten years of experience in the education field. His work involves writing news and articles, editing, and proofreading content related t... Read Full Bio
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Student Forum
Anything you would want to ask experts?Answered 11 hours ago
To access the 29 January 2025 shift 2 JEE Main paper, you can visit the official NTA website (jeemain.nta.nic.in) or trusted educational platforms like Shiksha and etc. where you can download the question paper PDF with solutions for both shifts of the exam; simply search for "JEE Main 2025 January
D
Beginner-Level 5
Answered 22 hours ago
Clearly, JEE main score is completely different from CRL i.e. common rank list.Cut-off for admission to NIT for obc category students varies for every NIT .
R
Beginner-Level 3
Answered Yesterday
Oftentimes students gain admission to one of over 300 colleges across India through their JEE Mains score performance in which 31 NITs together with 25 IIITs and 28 GFTIs are included. The leading institutions choosing JEE Mains scores as admission criteria include NIT Trichy and NIT Warangal togeth
K
Contributor-Level 10
Answered Yesterday
Different colleges throughout Bangalore possess varying admitted student cutoff scores for exams including JEE Mains and JEE Advanced. General category students need to score between 85-100 marks while the cutoff requirements for OBC students range from 70-80 percentile and the cutoff values for SC
K
Contributor-Level 7
Answered 2 days ago
Scoring 30 marks in the JEE Main 2025 exam held on January 23, Shift 2, is expected to place you in the 65th to 67th percentile range. This means you performed better than approximately 65% to 67% of the candidates who appeared for the exam.
Please note that these figures are based on previous years'
A
Contributor-Level 9
Answered 2 days ago
Admission to the Bachelor of Design (B.Des.) programme in India is primarily through the Undergraduate Common Entrance Examination for Design (UCEED), not JEE Main. Institutes like IIT Bombay, IIT Delhi, IIT Guwahati, IIT Hyderabad, and IIITDM Jabalpur offer B.Des. programs and accept UCEED scores.
K
A
Contributor-Level 9
Answered 2 days ago
You can visit the official NTA website "jeemain.nta.nic.in" and log in as a candidate to download the PDF of the question paper; you can also find it on educational platforms like Shiksha.com, which usually provide detailed solutions alongside the question paper.
Official source:
The most reliable pl
N
Contributor-Level 6
Answered 2 days ago
According to the latest information, the JEE Main cutoff for the General category in 2024 is around 93.23 percentile, with the following category-wise cutoffs: EWS - 81.32%, OBC - 79.67%, SC - 60.09%, and ST - 46.69%.
Key points to remember:
No official announcement yet for 2025:
The official JEE Main
Contributor-Level 9
Answered 2 days ago
According to available information, NIT Delhi is considered the best NIT for aerospace engineering, as it offers a dedicated "Mechanical and Aerospace Engineering" department, making it the most prominent NIT with a focused aerospace engineering program.
Key points to remember:
NIT Delhi:
Offers a ded
Contributor-Level 9
Answered 2 days ago
Yes, candidates seeking admission to the KPR Institute of Engineering and Technology BTech course need not give JEE Main. The institute also accepts TANCET entrance exam for admission. Aspiriong candidates must qualify the eligibility criteria set by the institute for the desired course. Students mu
A
Beginner-Level 5
JEE Main Notifications
Candidates need not have 75 percent marks in class 12 for appearing in JEE Main. As per the official brochure released by the NTA there is no minimum percentage required for appearing in the JEE Main. The requirement of 75 percent marks need not be associated with JEE Main. It is to be understood that 75 percent marks is required for admission to institutes which include NITs, IIITs, GFTIs and IITs. There are many institutes which offer admission on 60% and even less along with JEE Main. Candidates must clearly understand that the requirement of 75 percent marks in class 12 is only for taking admission in the institutes.