JEE Main 2024 cutoff required to qualify for JEE Advanced 2024 will be released by NTA. Minimum JEE Main marks required for JEE Advanced will be in the form of NTA percentile scores and will vary for Gen, OBC-NCL, SC, ST and Gen-EWS categories. Candidates can check here JEE Main cutoff marks for previous year all categories to know cutoff scores required to qualify the exam. If you are also looking for how much percentile is required for jee advanced then this article will give you complete details!
Candidates can check here the cutoff for JEE Mains 2024. Minimum marks in JEE Main 2024 to qualify for JEE Advanced has been announced by the National Testing Agency (NTA) along with the JEE Main 2024 result of session 2. The NTA has announced JEE Main second session result 2024. Candidates can also check below the previous year JEE Main cutoff which candidates need to have to qualify for JEE Advanced.
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Candidates who score above the minimum marks or JEE Main 2024 cutoff will only be allowed to appear for the JEE Advanced. JEE Main is the screening test for JEE Advanced which is conducted for admission to undergraduate engineering courses conducted by IITs. Since last year, the top 2.5 lakh candidates who qualify for JEE Main will be selected to appear for JEE Advanced 2024. Every candidate needs to score certain marks or above the cutoff for JEE Advanced.
Q: How many candidates appear in JEE Mains?
In JEE Main 2024, the total number of candidates who appeared in the exam is 11.7 lakh. This is the highest number ever since the inception of JEE Mains exam. Canddiates can see the gender-wise distribution of candidates below. Generally, the number of unique candidates appearing in JEE Main every year is around 10 Lacs in both sessions. Around 6-7 Lacs candidates appear in every session of JEE Mains. As there are several candidates appearing in both the sesisons, the total number would be around 12-13 Lacs with unique candidates around 10 lakh. The exact number of students is released by the NTA every year on the official website with category, gender and state-wise data. Candidates can check the number of candidates appearing in JEE Mains every year on this Shiksha page.
Q: What is the age limit to apply for JEE Main?
As per the JEE Main eligibility criteria released by the NTA there is no maximum or minimum age to apply for JEE Main. Candidates of any age can apply and appear in the JEE Main exam. The only criteria which is applicable is that the candidate can appear in JEE Mains for three consecutive years from the year of passing class 12. For example, if a candidate is applying for JEE Main 2024, candidate must have passed class 12 in 2022, 2023 or appearing in 2024.
Q: How many minimum marks are required to clear JEE Mains?
| JEE Main Application Form 2024 | JEE Mains 2024 Exam Date |
| JEE Main 2024 Result | JEE Main 2024 Answer Key |
NTA JEE Mains 2024 Cutoff
| Category |
JEE Main Cutoff 2024 (Percentile) |
|---|---|
| Unreserved (UR) |
100.0000000 to 93.2362181 |
| OBC-NCL |
93.2312696 to 79.6757881 |
| SC |
93.2312696 to 60.0923182 |
| ST |
93.2312696 to 46.6975840 |
| UR-PwD |
93.2041331 to 0.0018700 |
JEE Main 2023 Cutoff
Candidates can check here the cutoff for JEE Main 2023 released by the NTA.
| Category |
JEE Main 2023 Cutoff |
| Common Rank List |
90.7788642 |
| Gen-EWS |
75.6229025 |
| OBC-NCL |
73.6114227 |
| SC |
51.9776027 |
| ST |
37.2348772 |
| PwD |
0.0013527 |
JEE Main 2022 Cutoff for JEE Advanced
Candidates can check below the minimum marks required for JEE Advanced as per the last year's cutoff. Cracking any entrance exam solely depends on an effective study plan and the amount of hard work done by a candidate. With a little time left, here is a quick look at how much students need to score to qualify for the JEE Advanced 2023. JEE Main minimum marks required to qualify for JEE Advanced is given below.
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| Category | JEE Main Cutoff 2022 (Percentile) by NTA |
|---|---|
| Common Rank List (CRL) | 88.4121383 |
| GEN-EWS | 63.1114141 |
| Other Backward Classes (OBC-NCL) | 67.0090297 |
| Scheduled Caste (SC) | 43.0820954 |
| Scheduled Tribe (ST) | 26.7771328 |
| PwD | 0.0031029 |
The top 2.5 lakh candidates who qualify for the JEE Advanced would comprise students from unreserved as well as reserved categories. The exam conducting authority will publish the raw score obtained by a candidate in JEE Main as well as the corresponding percentile score. The cut-off for JEE Advanced would be based on the percentile score. Candidates can check the expected cut off percentile and score required to qualify for the JEE Advanced in the table above.
It is expected that the entrance test will be conducted online at 300 Centres for BTech/BE, BArch and BPlanning across the country. The exam acts as a gateway for admission to the Indian Institutes of Technology (IITs) – India’s premier engineering students.
Q: What is JEE Main Eligibility marks in class 12th?
NTA JEE Main eligibility criteria for candidates to appear in the exam is
- There is no minimum or maximum percentage required to appear in JEE Main. However, candidate need to have 75% marks in class 12 in addition to a valid JEE Main rank in order to get admission in NITs, IIITs and other CFTIs.
- Candidate must have passed class 12 in 2022, 2023 or appearing in 2024
- Candidate must have Maths and Physics as a compulsory subejct in class 12 for Paper 1 (BTech)
- For Paper 2A (BArch), it is compulsory to have Physics, Chemistry and Mathematics in class 12 and for Paper 2B (BPlan), candidate must have Mathematics in class 12
- There is no age limit to apply for JEE Main
Q: What is JEE Main Eligibility Criteria?
The eligibility criteria to appear in JEE Main are
- Candidate must have passed or appearing in class 12
- There is no age limit to appear in JEE Mains
- No minimum percentage is required to appear in the JEE Mains exam. 75% marks required after qualifying JEE Mains for admission in NITs, IIITs, and GFTIs
- Candidates must have Physics and Mathematics as compulsory subjects along with Chemistry/any other vocational subject for Paper 1 (BE/B.Tech). For paper 2, candidates need to have Mathematics as compulsory subject along with any other subject combination. Candidates can appear in JEE for three consecutive years from the year of passing class 12
Q: Can a commerce/non-science student apply for JEE Mains?
Candidates applying for JEE Main need to fulfill the following subject combination
- For Paper 1 (BE/BTech), candidates must have Physics and Maths in Class 12 and any one subject from Chemistry/Biology/Biotechnology/Technical vocational subject.
- For Paper 2A (BArch), candidates must have Physics, Chemistry, and Maths in Class 12.
- For Paper 2B (BPlan), candidates must have Maths in Class 12.
Q: Is the criteria of 75% marks in class 12 applicable in JEE Main 2025?
Hello candidate, there is no such requirement of 75% marks in class 12 for appearing in JEE Mains. The eligibility criteria of minimum 75% marks in class 12 is required at the time of admission in NITs, IIITs and GFTIs. You can apply and appear in JEE Mains 2025 irrespective of your class 12 marks. The detailed JEE Main eligibility criteria 2025 can be checked on the respective official website. You are further advised to carefully check the detailed eligibility criteria before filling the JEE Main application form 2025.
All the best!
Q: How do I know if I am qualified for appearing in JEE Advanced exam?
Candidates need to check the JEE Main cutoff mentioned on their JEE Main result/scorecard and see whether they have obtained aggregate percentile score equal to or above the cutoff. JEE Main cutoff is different for all categories. Candidates can check category-wise JEE Main cutoff on the Shiksha page as well as in their scorecard. Only those candidates who have score equal to or above then the cutoff are allowed to appear in JEE Advanced exam. Admission in IITs is though JEE Advanced while NITs, IIITs and GFTIs offer admission based on JEE Mains rank. The JEE Main cutoff for JEE Advanvced is released with the JEE Main final scorecard after the exam for both sessions are over.
NTA releases the JEE Main 2024 admit card on the official website for eligible candidates only. To download their JEE mains exam admit card, candidates must enter JEE Main login details like their application number and date of birth on the official website. The exam conducting authority is expected to release the official JEE Main 2024 answer key within 3 days post-conclusion of the exam.
Students and parents should note that the expected cutoff provided above is based on the cutoff for 2023. The exact cutoff for 2024 may vary. However, depending on the number of students who appear and the general trends observed over the years, the expected cutoff score remains the same with a variance range of about 5 marks either way.
The percentile of a candidate is the basis for calculating the JEE Main score. As candidates appear for the exam in different shifts of different days, the percentile scores of the students are normalized and calculated as per the formula available on the official website: jeemain.nta.nic.in. The exam conducting authorities will release the cut off for JEE Main only after the conclusion of the JEE Man 2024 April exam along with the JEE Main 2024 ranks and final results.
Also Read:
- How to Crack JEE Advanced 2024 in First Attempt?
- How to Crack JEE Advanced 2024 Without Coaching With Self Study
- JEE Advanced 2024: List of Courses Offered by IITs
JEE Main Cutoff Trends
| Category/Year | 2021 | 2020 |
| General | 87.8992241 | 90.3765335 |
| OBC-NCL | 68.0234447 | 72.8887969 |
| SC | 46.8825338 | 50.1760245 |
| ST | 34.6728999 | 39.0696101 |
| Gen-EWS | 66.2214845 | 70.2435518 |
| PwD | 0.0096375 | 0.0618524 |
JEE Main 2024 Dates
NTA has announced JEE Main 2024 exam dates for both January and April sessions. Candidates can check the same below:
| Events | January Session Dates | April Session Dates |
| Release of Application form | 01-Nov-2023 | 02-Feb-2024 |
| Last date to fill the form | 04-Dec-2023 | 02-Mar-2024 |
| Intimation of exam city to candidates | January 12, 2024 | March last week |
| Release of admit card | 20-Jan-2024 | March last week |
| JEE Main exam date | January 24 to February 1, 2024 | April 4 to 15, 2024 |
| Display of Answer key | Feb 6, 2024 | To be notified |
| Declaration of Result | 12-Feb-2024 | 25-Apr-2024 |
Read More:
- How to calculate JEE Main 2024 Percentile Score - Know Normalization Process
- How To Calculate JEE Main 2024 Rank From Percentile
- JEE Advanced 2024: List of IITs and Courses for Rank Within 1,000 to 5,000
- JEE Advanced 2024: List of IITs and Courses for Rank Within 5,000 to 10,000
- JEE Advanced 2024: List of IITs and Courses for Rank Within 10,000 to 30,000
JEE Main 2024 Minimum Marks FAQs
Q. What is the minimum percentile required to qualify JEE Advanced 2024?
A. Candidates must be among the top 2.5 lakh successful candidates of JEE Main to appear for the JEE Advanced. The NTA has revoked the criteria of the top 75 percent in the board exam or among op 20 percentile candidates in the 10 2 board to appear in the JEE Advanced 2024.
Q. Which IIT and engineering branch can a student get with 5000 rank?
A. With a rank of around 5000, candidates are likely to get Computer Science or Electrical Engineering in IIT Hyderabad. They may also get Mechanical Engineering in IIT Kanpur or IIT Roorkee.
Q. With 85 percentile in JEE Main, can I appear in JEE Advanced?
A. Candidates with 85 percentile in JEE Main will have a rank around 1.3 lakh. As the top 2.5 lakh students appear for JEE Advanced. You have a good possibility of appearing for the exam.
Q. What is the approximate rank for a candidate scored 150 marks in JEE Main?
A. Candidates with 150 marks in the JEE Main entrance exam can expect a rank between 24000 to 29000.
Q. What is the minimum rank for IIT Bombay?
A. Candidates must have a rank around or less than 3000 in JEE Main for admission to IIT Bombay. For admission to Computer Science, candidates are required to have a rank less than 100 in JEE Main entrance test.
Satyendra is an expert news writer and content editor at shiksha.com with over ten years of experience in the education field. His work involves writing news and articles, editing, and proofreading content related t... Read Full Bio
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Student Forum
Anything you would want to ask experts?Answered 19 hours ago
Yes, candidates can appear for the JEE Mains exam without 75% marks in their qualifying exam. The 75% criteria is only applicable at the time of admission into NITs, IIITs and GFTIs and for appearing in JEE Advanced.
For Gate exam there is no such criteria that in your B tech or BE degree you have to
Y
Contributor-Level 10
Answered 20 hours ago
You can't join Universal AI University's B.Tech programme without taking the JEE Main exam. They consider JEE Main scores, as well as MHT CET and CUET UG scores, for admission.
Contributor-Level 6
Answered Yesterday
With a 60 percentile in JEE Main, admission to Indian Institute of Space Science and Technology (IIST) Indore for a B.Tech programme is highly unlikely. IIST typically requires much higher JEE Advanced ranks for its B.Tech programs, as it is a premier institute focused on space and aerospace enginee
R
Contributor-Level 10
Answered Yesterday
The College of Engineering Trivandrum (CET) primarily admits students to its B.Tech programs through the Kerala Engineering Architecture Medical (KEAM) entrance examination, and not typically through JEE Main. Admission via JEE Main scores is not a standard pathway for CET, as the college follows st
R
Contributor-Level 10
Answered Yesterday
While NCERT books are essential for building a strong foundation in concepts, especially in Chemistry, they alone may not be sufficient to clear JEE Mains and Advanced. For JEE Mains, NCERT textbooks are highly effective for topics in Chemistry, Physics, and Mathematics, as they cover fundamental co
R
Contributor-Level 10
Answered Yesterday
No, not all JEE preparation books are available for free in online or offline modes. While some resources, like NCERT textbooks and certain free materials provided by coaching institutes or educational platforms, are accessible online, most renowned JEE books by authors like H.C. Verma, D.C. Pandey,
R
Contributor-Level 10
Answered Yesterday
Revising the JEE Mains 2025 syllabus in 1 month requires a plan first:-
The plan is -
Week 1: Physics Revision (Days 1-7)
1. Day 1-2 :- Mechanics (Kinematics, Dynamics, Work, Energy, Momentum)
2. Day 3-4 :- Electromagnetism (Electric Charges, Fields, Circuits, Magnetism)
3. Day 5-6 :- Thermodynamics, Wav
Contributor-Level 7
Answered Yesterday
The JEE Main 2025 Session 1 result is expected to be declared in the second week of February 2025. The Session 2 results will be declared in the third week of April 2025. The JEE Main result will be released online on the official website jeemain.nta.ac.in. To check the JEE Main result, candidates n
Contributor-Level 9
Answered Yesterday
To prepare effectively for JEE Main 2025 Mathematics, focus on scoring and easier topics first, like:
- Matrices & Determinants: Simple and scoring; practice operations and properties.
- Algebra: Focus on Quadratic Equations, Progressions, and Polynomials.
- Coordinate Geometry: Straight lines, circles, and
R
Contributor-Level 10
Answered 2 days ago
To get computer related branch the last year cutoff rank was almost 1.3lakh. The cutoff vary differently every year so this is a rough idea. The cutoff depends upon the number of students appering, difficulty of question paper. You can't get most accurate numbers.
K
Contributor-Level 6
Does the 75 percent criteria apply for GATE also or is it only for jee