Minimum JEE Main 2025 Marks Required to Qualify for JEE Advanced
Joint Entrance Exam (JEE) Main 2025 ( JEE Main )
Registration - 1 Feb '25 - 25 Feb '25
JEE Main 2025 cutoff required to qualify for JEE Advanced 2025 will be released by NTA. Minimum JEE Main marks required for JEE Advanced will be in the form of NTA percentile scores and will vary for Gen, OBC-NCL, SC, ST and Gen-EWS categories. Candidates can check here JEE Main cutoff marks for previous year all categories to know cutoff scores required to qualify the exam. If you are also looking for how much percentile is required for jee advanced then this article will give you complete details!
Minimum marks in JEE Main 2025 to qualify for JEE Advanced will be announced by the National Testing Agency (NTA) along with the JEE Main 2024 result of session 2. The NTA will announce the JEE Main second session result 2025 in April. Candidates can check here the cutoff for JEE Mains 2025 once released. Candidates can check below the previous year JEE Main cutoff which candidates need to have to qualify for JEE Advanced.
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Candidates who score above the minimum marks or JEE Main 2025 cutoff will only be allowed to appear for the JEE Advanced. JEE Main is the screening test for JEE Advanced which is conducted for admission to undergraduate engineering courses conducted by IITs. Since last year, the top 2.5 lakh candidates who qualify for JEE Main will be selected to appear for JEE Advanced 2025. Every candidate needs to score certain marks or above the cutoff for JEE Advanced.
Q: How many candidates appear in JEE Mains?
Q: How many minimum marks are required to clear JEE Mains?
Q: What is JEE Main Eligibility marks in class 12th?
NTA JEE Main eligibility criteria for candidates to appear in the exam is
- There is no minimum or maximum percentage required to appear in JEE Main. However, candidate need to have 75% marks in class 12 in addition to a valid JEE Main rank in order to get admission in NITs, IIITs and other CFTIs.
- Candidate must have passed class 12 in 2022, 2023 or appearing in 2024
- Candidate must have Maths and Physics as a compulsory subejct in class 12 for Paper 1 (BTech)
- For Paper 2A (BArch), it is compulsory to have Physics, Chemistry and Mathematics in class 12 and for Paper 2B (BPlan), candidate must have Mathematics in class 12
- There is no age limit to apply for JEE Main
| JEE Main Application Form 2025 | JEE Mains 2025 Exam Date |
| JEE Main 2025 Result | JEE Main 2025 Answer Key |
NTA JEE Mains 2024 Cutoff
| Category |
JEE Main Cutoff 2024 (Percentile) |
|---|---|
| Unreserved (UR) |
100.0000000 to 93.2362181 |
| OBC-NCL |
93.2312696 to 79.6757881 |
| SC |
93.2312696 to 60.0923182 |
| ST |
93.2312696 to 46.6975840 |
| UR-PwD |
93.2041331 to 0.0018700 |
JEE Main 2023 Cutoff
Candidates can check here the cutoff for JEE Main 2023 released by the NTA.
| Category |
JEE Main 2023 Cutoff |
| Common Rank List |
90.7788642 |
| Gen-EWS |
75.6229025 |
| OBC-NCL |
73.6114227 |
| SC |
51.9776027 |
| ST |
37.2348772 |
| PwD |
0.0013527 |
JEE Main 2022 Cutoff for JEE Advanced
Candidates can check below the minimum marks required for JEE Advanced as per the last year's cutoff. Cracking any entrance exam solely depends on an effective study plan and the amount of hard work done by a candidate. With a little time left, here is a quick look at how much students need to score to qualify for the JEE Advanced 2023. JEE Main minimum marks required to qualify for JEE Advanced is given below.
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| Category | JEE Main Cutoff 2022 (Percentile) by NTA |
|---|---|
| Common Rank List (CRL) | 88.4121383 |
| GEN-EWS | 63.1114141 |
| Other Backward Classes (OBC-NCL) | 67.0090297 |
| Scheduled Caste (SC) | 43.0820954 |
| Scheduled Tribe (ST) | 26.7771328 |
| PwD | 0.0031029 |
The top 2.5 lakh candidates who qualify for the JEE Advanced would comprise students from unreserved as well as reserved categories. The exam conducting authority will publish the raw score obtained by a candidate in JEE Main as well as the corresponding percentile score. The cut-off for JEE Advanced would be based on the percentile score. Candidates can check the expected cut off percentile and score required to qualify for the JEE Advanced in the table above.
It is expected that the entrance test will be conducted online at 300 Centres for BTech/BE, BArch and BPlanning across the country. The exam acts as a gateway for admission to the Indian Institutes of Technology (IITs) – India’s premier engineering students.
Q: Is the criteria of 75% marks in class 12 applicable in JEE Main 2025?
Hello candidate, there is no such requirement of 75% marks in class 12 for appearing in JEE Mains. The eligibility criteria of minimum 75% marks in class 12 is required at the time of admission in NITs, IIITs and GFTIs. You can apply and appear in JEE Mains 2025 irrespective of your class 12 marks. The detailed JEE Main eligibility criteria 2025 can be checked on the respective official website. You are further advised to carefully check the detailed eligibility criteria before filling the JEE Main application form 2025.
All the best!
Q: What is the passing marks for JEE Mains?
Q: I want to know about the most important chapters to qualify for JEE Mains in Physics.
Q: What is Qualifying marks for JEE Mains 2025?
Qualifying marks for JEE Mains 2025, also called qualifying percentile for JEE Mains will be announced by the NTA along with the session 2 result. Candidates must note that qualifying percentile for JEE Mains 2025 is the minimum percentile required to appear in JEE Advanced 2025. For admission to NIT or IIITs, there is no provision of qualifying marks in JEE Mains 2025 and admission is given based on All India Rank in JEE Mains exam. NTA will announce JEE Mains 2025 All India rank in April after session 2 exam results.
Q: How do I know if I am qualified for appearing in JEE Advanced exam?
Candidates need to check the JEE Main cutoff mentioned on their JEE Main result/scorecard and see whether they have obtained aggregate percentile score equal to or above the cutoff. JEE Main cutoff is different for all categories. Candidates can check category-wise JEE Main cutoff on the Shiksha page as well as in their scorecard. Only those candidates who have score equal to or above then the cutoff are allowed to appear in JEE Advanced exam. Admission in IITs is though JEE Advanced while NITs, IIITs and GFTIs offer admission based on JEE Mains rank. The JEE Main cutoff for JEE Advanvced is released with the JEE Main final scorecard after the exam for both sessions are over.
NTA releases the JEE Main 2025 admit card on the official website for eligible candidates only. To download their JEE mains exam admit card, candidates must enter JEE Main login details like their application number and date of birth on the official website. The exam conducting authority is expected to release the official JEE Main 2025 answer key within 3 days post-conclusion of the exam.
Students and parents should note that the expected cutoff provided above is based on the cutoff for 2024. The exact cutoff for 2025 may vary. However, depending on the number of students who appear and the general trends observed over the years, the expected cutoff score remains the same with a variance range of about 5 marks either way.
The percentile of a candidate is the basis for calculating the JEE Main score. As candidates appear for the exam in different shifts of different days, the percentile scores of the students are normalized and calculated as per the formula available on the official website: jeemain.nta.nic.in. The exam conducting authorities will release the cut off for JEE Main only after the conclusion of the JEE Man 2025 April exam along with the JEE Main 2025 ranks and final results.
Also Read:
- How to Crack JEE Advanced 2025 in First Attempt?
- How to Crack JEE Advanced 2025 Without Coaching With Self Study
- JEE Advanced 2025: List of Courses Offered by IITs
JEE Main Cutoff Trends
| Category/Year | 2021 | 2020 |
| General | 87.8992241 | 90.3765335 |
| OBC-NCL | 68.0234447 | 72.8887969 |
| SC | 46.8825338 | 50.1760245 |
| ST | 34.6728999 | 39.0696101 |
| Gen-EWS | 66.2214845 | 70.2435518 |
| PwD | 0.0096375 | 0.0618524 |
JEE Main 2025 Dates
NTA has announced JEE Main 2025 exam dates for both January and April sessions. Candidates can check the same below:
| Events | January Session Dates | April Session Dates |
| Release of Application form | 28-Oct-2024 | 31-Jan-2025 |
| Last date to fill the form | 22-Nov-2024 | 24-Feb-2025 |
| Intimation of exam city to candidates | January 10, 2025 | March last week |
| Release of admit card | 20-Jan-2025 | March last week |
| JEE Main exam date | January 22 to 30, 2025 | April 1 to 8, 2025 |
| Display of Answer key | Feb 6, 2025 (Tentative) | To be notified |
| Declaration of Result | 12-Feb-2025 | 15-Apr-2025 |
Read More:
- How to calculate JEE Main 2025 Percentile Score - Know Normalization Process
- How To Calculate JEE Main 2025 Rank From Percentile
- JEE Advanced 2025: List of IITs and Courses for Rank Within 1,000 to 5,000
- JEE Advanced 2025: List of IITs and Courses for Rank Within 5,000 to 10,000
- JEE Advanced 2025: List of IITs and Courses for Rank Within 10,000 to 30,000
JEE Main 2025 Minimum Marks FAQs
Q. What is the minimum percentile required to qualify JEE Advanced 2025?
A. Candidates must be among the top 2.5 lakh successful candidates of JEE Main to appear for the JEE Advanced. The NTA has revoked the criteria of the top 75 percent in the board exam or among op 20 percentile candidates in the 10 2 board to appear in the JEE Advanced 2025.
Q. Which IIT and engineering branch can a student get with 5000 rank?
A. With a rank of around 5000, candidates are likely to get Computer Science or Electrical Engineering in IIT Hyderabad. They may also get Mechanical Engineering in IIT Kanpur or IIT Roorkee.
Q. With 85 percentile in JEE Main, can I appear in JEE Advanced?
A. Candidates with 85 percentile in JEE Main will have a rank around 1.3 lakh. As the top 2.5 lakh students appear for JEE Advanced. You have a good possibility of appearing for the exam.
Q. What is the approximate rank for a candidate scored 150 marks in JEE Main?
A. Candidates with 150 marks in the JEE Main entrance exam can expect a rank between 24000 to 29000.
Q. What is the minimum rank for IIT Bombay?
A. Candidates must have a rank around or less than 3000 in JEE Main for admission to IIT Bombay. For admission to Computer Science, candidates are required to have a rank less than 100 in JEE Main entrance test.
Satyendra is an expert news writer and content editor at shiksha.com with over ten years of experience in the education field. His work involves writing news and articles, editing, and proofreading content related t... Read Full Bio
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Student Forum
Anything you would want to ask experts?Answered Yesterday
Yes you have a high chance of getting a seat in JEE Mains as the PWD students have lower cut off marks so 40-80 should be sufficient enough.
And PWD students get 5% seat reservations so the chances are high.
With this mark you may not get admission in top NIT but sure will get in lower level NIT.
You
A
Beginner-Level 5
Answered Yesterday
Yes you can correct the income details.
For correction first look for the correction window to open in the official JEE site
If the correction window is open login to the account.
Select the edit option and correctly enter your income details.and submit for review.
If the correction window is closed t
A
Beginner-Level 5
Answered Yesterday
Yes, admission to B.Tech at Chandigarh University, UP Campus is available through JEE Mains scores. The university offers a scholarship scheme based on the All India Rank (AIR) of candidates in the JEE Mains examination. The scholarship percentage varies according to the rank, which helps students r
V
Beginner-Level 3
Answered Yesterday
Hello! Taking an early drop for JEE 2026 is a great decision if you're determined to improve your rank and secure a seat in your dream college. Since you've already attempted JEE Mains once, you have a clear idea of the exam pattern and your strengths and weaknesses. Start by analyzing your performa
R
Contributor-Level 10
Answered 3 days ago
Yes, candidates with a valid score in JEE Main can get admission in BTech programme of BASU Patna. However, it is not mandatory to have a JEE Main score. Candidates can also get admission in BTech with BCECE entrance exam score. Bihar Combined Entrance Competitive Examination Board conducts pen and
N
Contributor-Level 10
Answered 3 days ago
As per 2024, the closing ranks were,
B.Tech Computer Science = 1388428
B.Tech Civil Engineering = 1157
B.Tech Electrical and Electronics Engineering = 13217
S
Contributor-Level 6
Answered 4 days ago
The two-session Joint Entrance Examination (JEE) Main 2025 schedule has been released by the National Testing Agency (NTA). Session 2 is set for April 1–8, 2025, while Session 1 is set for January 22–30, 2025. Candidates can choose to attend one or both sessions, whichever they would like. When ca
N
Contributor-Level 10
Answered 5 days ago
NTA has released JEE Main 2025 Session 2 Application form. The link to apply for sesison 2 is available on the website jeemain.nta.nic.in. JEE Mains 2025 registration last date session 2 is February 25.
S
Contributor-Level 10
Answered 5 days ago
The NTA has announced JEE Mains 2025 result date session 1. As per the schedule, JEE Main result 2025 session 1 will be announced by February 12. JEE Mains result link will be available on the wesbite jeemain.nta.nic.in. The JEE Main 2025 result scorecard will have details of candidate percentile sc
S
Contributor-Level 10
Answered 5 days ago
Your JEE Mains registration form must show General for category selection because the National Testing Agency (NTA) administers this Central Government-run national-level examination. The NTA uses Central Government reservation guidelines which exclude state-level OBC categorizations from eligibilit
K
Beginner-Level 5
In JEE Main 2024, the total number of candidates who appeared in the exam is 11.7 lakh. This is the highest number ever since the inception of JEE Mains exam. Canddiates can see the gender-wise distribution of candidates below. Generally, the number of unique candidates appearing in JEE Main every year is around 10 Lacs in both sessions. Around 6-7 Lacs candidates appear in every session of JEE Mains. As there are several candidates appearing in both the sesisons, the total number would be around 12-13 Lacs with unique candidates around 10 lakh. The exact number of students is released by the NTA every year on the official website with category, gender and state-wise data. Candidates can check the number of candidates appearing in JEE Mains every year on this Shiksha page.