Probability Distribution: Overview, Questions, Preparation

Probability 2021 ( Probability )

Rachit Kumar Saxena

Rachit Kumar SaxenaManager-Editorial

Updated on May 12, 2021 06:52 IST

What is Probability Distribution?

Probability is the measure of the chance of occurrence of any event. A list of all the possible outcomes is known as the sample space. If an event E occurs, its probability is denoted by P(E).
The conditional probability of an event occurring concerning the occurrence of another event is given as-

P(M|N)= (Number of events favourable to M N) / (Number of events favourable to N)
= n (M N) / n(N).

Random Variable:

A random variable is a real numbered entity. The domain of a random variable is the sample space of a random experiment.

A descriptive depiction of the values of the random variable along with their associated probabilities is known as the probability distribution of that random variable.

Probability Distribution:

The probability of a random variable V is given as -
V : v1, v2, v3, ... , vn
P(V): p1, p2, p3, …, pn

So, the probability distribution lists all possible variables and the outcome probabilities. The sum of all probabilities in a probability distribution must be one.

Probability_Distribution

Weightage of Probability Distribution

The topic “probability distribution” is a part of the chapter “Probability” in the class 12 mathematics syllabus. This topic carries a weightage of around 7-8 marks in the examination.

Illustrated Examples on Probability Distribution

 1. A discrete random variable X has the following probability distribution:

V

1

2

3

4

5

6

7

P(V)

K

2K

2K

3K

K2

2K2

7K2 +K

Find the value of K. Also, calculate the mean.

Solution:

We know that,

P_D

So, K + 2K+ 2K + 3K + K2 + 2K2 + 7(7K2 +K) = 1

=> 10K2 + 9K- 1= 0 => (10K -1)(K+1) =0

=> K= 1/10 or K= -1

Since probability cannot be negative, K= 1/10.

Mean=

P_D =   P_D_2
=> Mean = 1 x K + 2x 2K + 3x 2K + 4x 3K + 5x K2 + 6x 2K2 + 7x 7K2

= 1 x (1/10) + 2x 2(1/10) + 3x 2(1/10) + 4x 3(1/10) + 5x (1/10)2 + 6x 2(1/10)2 + 7x {7(1/10)2 + 1/10}

= 1/10 + 4/10 + 6/10 + 12/10 + 5/100 + 12/100 + 49/100+ 7/10

Mean= 3.66

2.Show the probability distribution of the number of heads in three tosses of a coin.

Solution:

Let D denote the number of heads tossed. So, D can take the values 0, 1, 2, 3. When a coin is tossed three times, we get

Sample Space S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}

P (D = 0) = P (no head) = P (TTT)= ⅛

P (D = 1) = P (one head) = P (HTT, THT, TTH) = ⅜ 

P (D = 2) = P (two heads) = P (HHT, HTH, THH) = ⅜ 

P (D = 3) = P (three heads) = P (HHH)= ⅛ 

Hence, the probability distribution of D is given as-

D

0

1

2

3

P(D)

1/8

3/8

3/8

1/8

FAQs on Probability Distribution

Q: What are the conditions of the probability distribution?

A: The two conditions for a probability distribution are Each probability of the random event should lie between zero and one. The sum of all outcomes of a random experiment must be one.

Q: What are the types of the probability distribution?

A: The probability distribution is classified as—cumulative probability distribution and discrete probability distribution.

Q: What are some examples of the normal probability distribution?

A: Roll of dice, toss of a coin, weight of population, size of clothes, students performance report, are all examples of a normal probability distribution.

Q: What is a binomial probability distribution?

A: The word binomial means this distribution works on only two outcomes. A binomial distribution is used when the outcomes are either of the two possible cases, such as positive and negative results.

Q: What is the Poisson probability distribution?

A: The Poisson probability distribution represents the probability of a given number of events happening in a fixed time or space.

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Probability Exam

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