How To Calculate JEE Main 2024 Rank From Percentile: Criteria and Method

Joint Entrance Exam (JEE) Main 2025 ( JEE Main )

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Exam On: 22 Jan '25 - 24 Jan '25

Updated on Apr 25, 2024 01:11 IST
Students who will appear for JEE Main 2024 can read the article below to calculate the approximate JEE Main 2024 rank through percentile score.
The National Testing Agency (NTA) will announce the JEE Main 2024 result session 2 in the form of a percentile score. The All India Rank of candidates in JEE Main 2024 will be calculated by taking the best score out of two attempts. Shiksha received numerous queries from candidates who appear for JEE Main. Two of the most commonly asked questions are:
  • How to calculate JEE Main rank from percentile
  • Can JEE Main rank be calculated from percentile score?

While some experts believe that candidates cannot calculate JEE Main Rank from the percentile score of just one examination, others believe the opposite. Let’s discuss both cases in this article.

Latest News: JEE Main 2024 Session 2 Result OUT Live Updates

⇒ JEE Main 2024 Rank Predictor

⇒ JEE Main 2024 College Predictor

Minimum JEE Main marks to qualify for JEE Advanced

How To Calculate JEE Main 2024 Rank From Percentile

JEE Main Result 2024 JEE Main 2024 Marks vs Percentile
JEE Main Question Papers JEE Main Cutoff

Use your JEE Main 2024 Percentile and predict your Rank and the Colleges you are eligible for using Shiksha's JEE Main Rank and College Predictor.Get cut-off information for 600 colleges and 2500 colleges  

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How to calculate JEE Main 2024 rank from Percentile?

Candidates can analyze their NTA scores and calculate their approximate JEE Main rank through their percentile scores. Here’s how.

Take the total number of candidates who appeared for the JEE Main exam as "N". The exam is conducted in four days in two slots (4 days x 2 slots = 8 sessions in total). So, "S" number of students took the exam in each session. Note that the JEE Main results/scorecard mentions only the NTA score for each subject and not the subject-wise marks secured by candidates. The percentile score is displayed against each of the subjects and the overall percentile score is calculated up to 7 decimals using a pre-determined formula.

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For more information on how JEE Main 2024 Percentile score is calculated, read this article on How to calculate JEE Main 2024 Percentile Score - Know Normalization Process

So, to convert your JEE Main Percentile into a Rank, you need the following figures:

  1. Your NTA score
  2. Total number of students who have appeared for the exam
  3. Percentage of students below or equal to your marks
  4. Percentage of students above your marks
  5. Number of students above your marks

 While the data for the first two aspects are easily available, the figures for the other three data points are difficult to find. To calculate these, here's what you need to do.

Q:   Is 75 percent marks in class 12 required for JEE Mains?

A:

Candidates need not have 75 percent marks in class 12 for appearing in JEE Main. As per the official brochure released by the NTA there is no minimum percentage required for appearing in the JEE Main. The requirement of 75 percent marks need not be associated with JEE Main. It is to be understood that 75 percent marks is required for admission to institutes which include NITs, IIITs, GFTIs and IITs. There are many institutes which offer admission on 60% and even less along with JEE Main. Candidates must clearly understand that the requirement of 75 percent marks in class 12 is only for taking admission in the institutes.

Q:   What is CRL in JEE Main Cutoff?

A:
CRL stands for the Common Rank List. NTA releases the cutoff in several categories one of which is CRL. Basically, CRL means unreserved category. Candidates belonging to unreserved category need to have JEE Main cutoff equal to or more than the CRL cutoff. The other categories for which cutoff is released are Gen-EWS, Open-PwD, OBC-NCL, SC and ST.

Q:   What is the expected NIT Calicut JEE Main cutoff 2024?

A:

Going as per the past three year trends candidates can expect the closing ranks for NIT Calicut JEE Main cutoff 2024 Round 1 Seat Allotment for top specialisations between the following range: 

Let’s assume:

Your NTA score =

P

Total Number of Students =

N

Percentage of students below or equal to your marks =

P

For example: if you have secured a 70 percentile in JEE Main, which means that 70% of the candidates who appeared for JEE Main are below or at the same level as you are

Percentage of students above your marks =

100 - P

Number of students above your marks

((100 – P)/100)*N

Now, the formula to calculate JEE Main Rank from Percentile Score is:

((100 – P)/100)*N 1

The rank generated will be the probable All India Rank (AIR) you can expect to secure in JEE Main. The actual rank might differ owing to different factors.

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Can JEE Main rank be calculated from percentile score?

According to an IIT Bombay expert, it’s difficult to derive an AIR through one’s percentile score. To help you understand why you cannot calculate JEE Main rank from percentile scores of the first attempt of the exam, let’s take the example of two students.

Student

Percentile Score – January

Percentile Score – April

AIR (All India Rank)

A

96 percentile

65 percentile

?

B

60 percentile

98 percentile

?

Student A secured 96 percentile in the JEE Main January exam, while Student B got 60 percentile in the same session of the examination. Now, the same set of students has secured the 65 percentile and 98 percentile respectively in JEE Main.

Q:   What is NIT Rourkela cutoff for BTech?

A:

NIT Rourkela cutoff 2024 has been released across various specialisations in opening and closing ranks. NIT Rourkela BTech cutoff 2024 ranged between 2680 and 35593 for the General AI category candidates, wherein BTech in CSE is the most competitive course. The easiest BTech specialisation to secure admission in is B.Tech. in Ceramic Engineering + M.Tech. in Industrial Ceramic Engineering. For a detailed NIT Rourkela branch-wise cutoff 2024, candidates can refer to the table below for the Round 1 cutoff. The cutoff mentioned below is for the General category under the AI Quota.

Course2024
B.Tech. in Biomedical Engineering28053
B.Tech. in Ceramic Engineering34492
B.Tech. in Chemical Engineering16708
B.Tech. in Civil Engineering23425
B.Tech. in Computer Science and Engineering2680
B.Tech. in Electrical Engineering8770
B.Tech. in Electronics and Communication Engineering5053
B.Tech. in Mechanical Engineering13682
B.Tech. in Metallurgical and Materials Engineering27499
B.Tech. in Mining Engineering31497
B.Tech. in Biotechnology27533
B.Tech. in Electronics and Instrumentation Engineering8646
B.Tech. in Industrial Design27601
B.Tech. + M.Tech. in Chemical Engineering18843
B.Tech. in Ceramic Engineering + M.Tech. in Industrial Ceramic Engineering35593
B.Tech. + M.Tech. in Metallurgical and Materials Engineering33676
B.Tech. + M.Tech. in Mining Engineering32461
Bachelor of Architecture (B.Arch.)439
B.Tech. in Food Process Engineering34726
B.Tech. in Artificial Intelligence3880

Q:   What is the cutoff for BTech at NIT Andhra Pradesh for OBC category?

A:

NIT Andhra Pradesh BTech cutoff 2024 for BTech courses ranged between 25704 and 91199 for OBC category. Wherein, the most competitive course was BTech in Computer Science and Engineering and the least competitive course was BTech in Biotechnology. While the admissions are based on the scores/rank obtained in JEE Main, the last cutoffs also change a lot depending on All India quota or Home State. It also varies if the applicant is a female.

Q:   Can I get NIT with 95 percentile in JEE Main?

A:

It is possible for you to secure a seat in an NIT (National Institute of Technology), although it may not guarantee your preferred branch or institute. If your percentile is above 96, your chances of getting into a respectable NIT increases, but you may need to compromise on your branch selection. However, if you aim for a decent NIT with a preferred branch in the core field, you would need to score above 97.5%. On the other hand, if your goal is to get admission to a top college with the CSE (Computer Science and Engineering) branch, your score would need to be higher than 99.4%.

Q:   What is the cutoff for BTech in Computer Science and Engineering at NIT Hamirpur for other than General categories?

A:

The last year 2022 cutoff ranks for BTech in Computer Science and Engineering at NIT Hamirpur - National Institute of Technology other than General category are - 17445 for OBC, 1663 for SC, 578 for ST, 16770 for EWS, 187395 for PWD. While the admissions are based on the scores/rank obtained in JEE exam, the last cut offs also change a lot depending on All India quota or Home State. It also varies if the applicant is a female.

Q:   How to calculate percentile in JEE?

A:

NTA uses a formula to calculate NTA score in JEE Main. The formula used is 

JEE-Main-NTA-Score-Formula

 

Now, the general thought process of candidates after seeing the percentile score of the January attempt would be that Student A has performed better than Student B in JEE Main. But, that’s not the case. Because, on the second attempt of the exam, Student B secured a better percentile than Student A. As per NTA, JEE Main ranks or rank list will be published after taking into account the better of the two four NTA scores of all candidates who have appeared for JEE Main January and April sessions. Furthermore, to determine JEE Main results and rank list, the agency will adopt the process of normalization which will be based on percentile calculation. Thus, deriving one’s rank from the percentile score of the first attempt is not possible as the exam is being conducted twice.

Important note:

  • The percentile is not the same as a percentage.
  • JEE Main merit list will be prepared based on percentile scores and not on the raw marks secured by aspirants in the exam.

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FAQs regarding JEE Main Percentile and Ranks

Q. Is percentile equal to a percentage?

A. No, percentile and percentage are totally different from each other. The percentile rank of a score is the percentage of scores in its frequency distribution that are equal to or lower than it.

Q. What is percentile vs percentage?

A. The percentile is relative to the score that other people made on the test, while the percentage is your individual score. Percentile is used when scoring standardized tests and is used in statistics.

Q. What is the percentile in JEE Main?

A. JEE Main percentile score will be the normalised score for the exam and not the raw marks of the test taker.

Q. Is 100 percentile possible?

A. If the "percentage below or equal to" definition is used, then, yes, we can have 100 percentile. However, if we use the "percentage below" definition, then, no, you cannot have a 100 percentile.

Q. Can I get nit with 94 percentile?

A. According to your percentile, your approximate rank is 66,000. If you have a home state quota, then you will definitely get an NIT.

Q. Is 97 percentile good in JEE mains?

A. Scoring 97% is good, so, when you are looking for the colleges that you can get at such percentile. It can be an NIT.

Q. Can I get nit with 70 percentile?

A. No, there is no chance to get admission to any NITs with a 70 percentile for the general category. For the general candidates, at least 97 percentile is required to get a seat in NITs. You can try to get admission to other good engineering colleges.

Q. Can I get nit with 90 percentile OBC?

A. You have very low chances of getting admission in any of the NITs based on your JEE Main percentile score and category rank. Try for admission in private colleges through state counselling.

Q. What percentile is required for IIIT?

A. Every year cut off score for IIIT Hyderabad's last closing branch is around 250-260 or 99 percentile, which means a rank of around 1000 will be required for admission.

Q. Is IIIT better than nit?

A. It depends on which IIIT/NIT you are getting according to your rank. In terms of placement, faculties and infrastructure some IIITs are far better than many NITs.

About the Author

Satyendra is an expert news writer and content editor at shiksha.com with over ten years of experience in the education field. His work involves writing news and articles, editing, and proofreading content related t... Read Full Bio

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Answered 18 hours ago

Hello Mohit, I hope you are doing fine .

As you are asking for the cutoff of JEE mains, here is the information:

      Category  Percentile (expected) 

  • GENERAL 91-95
  • EWS 79-83
  • OBC-NCL 77-83
  • SC 58-62
  • ST  44-48

So the JEE Mains result will be announced on feb12, 2025. You can the result on the official Websi

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  • Session 1 Result: Expected by February 12, 2025.

  • Session 2 Result: Expected by April 17, 2025.

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Vishwajeet Ghosh

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Yes, Mangalmay Institute of Management and Technology accepts JEE Main scores for admission to its BTech courses. To be eligible candidates must pass Class 12 or equivalent with Physics and Mathematics as compulsory subjects and one of the optional subjects-Chemistry/ Biotechnology/ Biology with at

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No, admissions in the BTech course at NEHU Shillong is not possible without JEE Main. Students must clear JEE Main exam to get admission in this university's BTech course. At the undergraduate level, the university offers BTech course to students. The total tuition fee for the BTech course is INR 5,

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Hi, hope you're doing well.

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