The CSIR UGC NET 2025 notification will be released on the official website for the June session at csirnet.nta.ac.in. The authority will also release the CSIR NET 2025 exam dates and the application form along with the notification. Scroll down to know more about the CSIR NET 2025, including the application process, dates, syllabus, exam pattern, eligibility criteria, and more.
CSIR NET 2025: The CSIR NET is the Council of Scientific and Industrial Research National Eligibility Test. The NTA will conduct the CSIR UGC NET 2025 exam to select the candidates who are eligible as lecturers and Junior Research Fellow persons in the faculty of science. The CSIR NET 2025 exam will be held in an online mode for five subjects: Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life Sciences, Mathematical Sciences and Physical Sciences. The authority will release the CSIR NET 2025 notification for the June session on the official website at csirnet.nta.ac.in. Candidates can read more about the CSIR NET exam including the eligibility, application process, important dates, exam pattern, syllabus, exam pattern and more.
CSIR NET 2025 Exam Highlights
Candidates can check below for an overview of the CSIR UGC NET exam, including the conducting body, exam mode and frequency, number of candidates, contact details and more.
Exam Features |
Exam Particulars |
---|---|
Exam Name |
CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) |
Conducting Body |
National Testing Agency (NTA) |
Exam Level |
National |
Exam Frequency |
Twice a year |
Mode of Exam |
Online - CBT (Computer-Based Test) |
Exam Fees |
|
Pattern of Examination |
Objective Type |
Exam Duration |
180 minutes (3 hours) |
Exam Time |
Shift 1 - 09:00 am to 12:00 noon |
No. of Papers and Total Marks |
|
Language/Medium of Exam |
English and Hindi |
Exam Purpose |
To determine the eligibility of candidates for Junior Research Fellowship (JRF) and for Lectureship (LS)/ Assistant Professor in the universities and colleges of India |
Official Website |
csirnet.nta.ac.in |
CSIR NET 2025: Important Dates
Q: How many marks are required to qualify for the CSIR NET 2024 exam?
Q: What are the benefits of qualifying CSIR NET?
There are many benefits of qualifying for CSIR NET, some of which are mentioned below;
1- You can get a CSIR NET JRF fellowship/Ph.D. Fellowship of INR 31,000 per month for 2 years as JRF followed by an INR 35,000 per month fellowship for 3 additional years.
2- Get opportunities to work in top Research Laboratories in positions like Junior Research Fellowship, Senior Research Fellowship, Project Associate, Research Associate, Project Fellow, and Senior Project Fellow are positions which you can apply for.
3-Numerous Public sectors companies like Indian Oil, Hindustan Petroleum, and ONGC, hire CSIR NET and GATE qualified every year for various posts with an average salary from INR 40,000 to INR 80,000 per month.
4- You can get an opportunities to join a top university as an Assistant Professor or guest lecturer.
5- CSIR NET qualification increases your CV Weightage/Helps in getting higher preferences in getting jobs.
Q: How many times is CSIR NET conducted in a year?
Candidates can check below for CSIR NET 2025 important dates.
Events |
Dates |
---|---|
CSIR NET application form dates |
to be updated |
Last date of payment of CSIR NET 2025 application fee |
to be updated |
Availability of CSIR NET 2025 correction window |
to be updated |
CSIR NET 2025 June Exam |
to be updated |
CSIR NET Exam Date 2024
The National Testing Agency (NTA) will reveal the CSIR NET Exam Date 2025 for the June session.
CSIR NET 2025 Exam Schedule & Shift-Timings
The NTA will release the CSIR NET 2025 exam schedule and shift timings on the official website. Once released, we will provide it here also.
Also Read: CSIR NET Syllabus 2024 in Detail
CSIR NET 2025 Notification
The CSIR NET notification 2025 will be released by the National Testing Agency (NTA) for the June session on the official website at csirnet.nta.ac.in. The notification consists of the important details of the exam like:
- Application process
- Exam dates and schedule
- CSIR NET eligibility criteria
- CSIR NET exam pattern and syllabus
- CSIR NET qualifying marks and cut-off criteria
- Validity of CSIR NET
- Exam centres list
- Admit card
- Verification of eligibility, etc.
Q: If I meet the CSIR NET cut-off for my subject, what will happen next?
Q: Is it mandatory to appear for all three parts of the CSIR NET exam?
Direct link to download CSIR NET 2025 notification pdf: to be updated here
Also Read: CSIR NET Exam Date 2025
CSIR NET 2025 Application Form
The NTA will release the CSIR NET 2025 application form for the June session along with the CSIR NET 2025 Notification. Candidates will be able to apply for the CSIR NET 2025 by registering and logging in to the official website through the required credentials. Check below the steps to fill out the CSIR NET 2025 application form:
First, candidates are required to get themselves registered online
Login with the credentials used during the registration process
Fill out the application form available with the application number & password shared on your email ID and phone number
Upload the scanned documents as per requirements. The instructions for the same will be available there
After submitting the application form, pay the application fee through the online payment gateways available
Direct link to fill out the CSIR NET 2025 Application Form: to be updated here
CSIR NET 2025 Eligibility Criteria
The eligibility criteria of CSIR NET 2025 play a crucial role before filling out the CSIR NET 2025 application form. It is also important for a candidate to meet the CSIR NET eligibility. If in case candidates are found ineligible by the NTA at any stage, then they will be disqualified for the exam. Therefore, it is important for a candidate to go through the CSIR NET eligibility criteria as prescribed by the NTA below. The CSIR NET Eligibility 2024 comprises the following aspects:
- Nationality
- CSIR NET Age limit
- Relaxation in upper age limit
- Educational Qualification
Nationality
Those candidates who are Indian citizens are eligible to apply for CSIR NET 2025 exam.
Age Limit
JRF: Not more than 30 years as on the first day of the month in which the examination is concluded that is February 2025. A relaxation upto 5 years is provided to the candidates belonging to OBC-NCL/SC/ST/PwD/Third gender categories and to women applicants.
For the position of Assistant Professor or for applying for PhD programs, there is no upper age limit.
Assistant Professor: There is no upper age limit in applying for Joint CSIR UGC-NET for Assistant Professor.
Admission to PhD: There is no upper age limit in applying for Joint CSIR-UGC-NET for Admission to PhD.
Education Qualification
It is important to consider the qualification. Candidates need to possess either of the below-mentioned qualifications with at least 55 per cent marks (for General and OBC) or 50 per cent marks (for Scheduled Caste (SC)/Scheduled Tribe (ST)/Persons with Disability (PwD) candidates).
MSc or equivalent degree |
Integrated BS-MS |
BS (4 years) |
BE |
BTech |
BPharma |
MBBS |
On the basis of a Master’s Degree or Equivalent Degree
- Candidates who are enrolled for MSc or have completed MSc or equivalent degree/ Integrated BS-MS/ BS-4 years/ BE/ BTech/ BPharma/ MBBS as of the last date of the CSIR NET application 2025 are also eligible to apply under the Result Awaited (RA) category.
- The condition of RA category candidates is that they should complete their qualifying degree with the required percentage of marks within the validity period of two years from the date of declaration of the Joint CSIR UGC NET result failing which they shall be treated as disqualified.
On the basis of a BSc (Hons) or equivalent degree or candidates enrolled in an integrated MS-PhD program
Candidates who hold a BSc (Hons) or equivalent degree or candidates enrolled in an integrated MS-PhD program with at least 55 per cent marks (50 per cent for SC/ST/PwD candidates) are also eligible to apply for the CSIR NET exam. Also, candidates who hold an undergraduate degree will be eligible for CSIR fellowship only after getting registered for PhD/Integrated PhD course within the validity period of two years, as per the official website.
On the basis of a Bachelor’s Degree
- Those candidates who possess only a Bachelor's degree are eligible to apply for Junior Research Fellowship (JRF) only and not the Lecturership (LS)/Assistant Professor. That is, BE/ BS/ BTech/ BPharma/ MBBS final year/ result-awaited candidates are eligible to apply for JRF only. Such candidates are not eligible to apply for LS.
- BSc (Hons.) final year/Result awaited candidates are also not eligible to apply.
Others
- Candidates who possess a PhD degree and who have passed their master’s before September 19, 1991, with at least 50 per cent marks are eligible to apply for lectureship only.
- The eligibility for Lectureship/Assistant Professor of NET qualified candidates is subject to fulfilling the criteria laid down by UGC.
CSIR NET 2025: Exam Pattern
CSIR NET 2025 Exam pattern is more crucial part of the examination. The CSIR NET 2025 Question paper will be divided into three sections: Part A, B and C. All parts will consist of objective type, multiple choice questions. There will be no break between papers.
Part 'A' shall be common to all subjects. It consists of maximum of 20 questions of General Aptitude. Candidates need to answer any 15 questions for two marks each. The total marks allocated to this section shall be 30 out of 200. This part also consists of General Aptitude questions that emphasis on logical reasoning, graphical analysis, analytical and numerical ability, quantitative comparison, series formation, puzzles, teaching/research aptitude, etc.
Part B and C consist of questions based on subject chosen by candidates from the following five subjects namely Earth, Atmospheric, Ocean and Planetary Sciences, Chemical Sciences, Life Sciences, Mathematical Sciences and Physical Sciences.
The subject-wise scheme of examination is mentioned below:
Chemical Science (701)
Particulars |
Part A |
Part B |
Part C |
Total |
---|---|---|---|---|
Total Questions |
20 |
40 |
60 |
120 |
Max no of questions to attempt |
15 |
35 |
25 |
75 |
Marks for each correct answer |
2 |
2 |
4 |
200 |
Negative marking of 25% |
0.5 |
0.5 |
1 |
- |
Earth, Atmospheric, Ocean and Planetary Sciences (702)
Particulars |
Part A |
Part B |
Part C |
Total |
---|---|---|---|---|
Total Questions |
20 |
50 |
80 |
150 |
Max no of questions to attempt |
15 |
35 |
25 |
75 |
Marks for each correct answer |
2 |
2 |
4 |
200 |
Negative marking- 25% in Part A & B and 33% in Part C |
0.5 |
0.5 |
1.32 |
|
Life Sciences (703)
Particulars |
Part A |
Part B |
Part C |
Total |
---|---|---|---|---|
Total Questions |
20 |
50 |
75 |
145 |
Max no of questions to attempt |
15 |
35 |
25 |
75 |
Marks for each correct answer |
2 |
2 |
4 |
200 |
Negative marking of 25% in Part A, B & C |
0.5 |
0.5 |
1 |
- |
Mathematical Sciences (704)
Particulars |
Part A |
Part B |
Part C |
Total |
---|---|---|---|---|
Total Questions |
20 |
40 |
60 |
120 |
Max no of questions to attempt |
15 |
25 |
20 |
60 |
Marks for each correct answer |
2 |
3 |
4.75 |
200 |
Negative marking in Part A & B of 25% and no negative marking in Part C |
0.5 |
0.75 |
0 |
- |
Physical Sciences (705)
Particulars |
Part A |
Part B |
Part C |
Total |
---|---|---|---|---|
Total Questions |
20 |
25 |
30 |
75 |
Max no of questions to attempt |
15 |
20 |
20 |
55 |
Marks for each correct answer |
2 |
3.5 |
5 |
200 |
Negative marking of 25% for Part A, B and C |
0.5 |
0.875 |
1.25 |
- |
CSIR NET 2025 Syllabus
Candidates can check below the CSIR NET Syllabus 2025 for all the five subjects namely Earth, Atmospheric, Ocean and Planetary Sciences, Chemical Sciences, Life Sciences, Mathematical Sciences, and Physical Sciences.
CSIR NET 2025 Part A Syllabus
The syllabus for CSIR NET Part A is same for all five subjects. Part A contains questions related to General Science, Quantitative Reasoning, and Analysis and Research Aptitude. Scroll down for Part A syllabus.
Reasoning: Analytical Reasoning, Syllogisms, Analogies, Directions, Coding-Decoding, Classification, Alphabet Series, Symbols and Notations
Similarities and Differences, Number Series, Blood Relationships, Arrangements, Statements, Data Sufficiency, Non-verbal Reasoning, Visual Ability, Graphical Analysis, Data Analysis, etc.
Quantitative Aptitude: Simplifications, Number System, Average, Algebra, Percentage, Time & Work, Simple & Compound Interest, Time & Speed, HCF, LCM Problems, Area, Profit & Loss, Bar Graph, Pictorial Graph, Pie Chart, Ratio & Proportion, Permutation & Combination, etc.
Data Interpretation & Graphical Analysis: Mean, Median, Mode, Measures of Dispersion, Graphical Analysis: Bar Graph, Line Graph, Pie-Chart and Tabulation, etc.
CSIR NET Syllabus: Part B & C
Scroll down for a detailed syllabus, which will help candidates score better in the CSIR NET exam and also provide better clarity for the topics that are required to be covered.
Earth Sciences: Geology, Applied Geology, Physical Geography, Geophysics, Meteorology, Ocean Sciences, etc.
Chemical Sciences: Inorganic Chemistry, Physical Chemistry, Organic Chemistry, Interdisciplinary topics, etc.
Life Sciences: Molecules and their Interaction, Cellular Organization, Developmental Biology, Diversity of Life Forms, Cell Communication and Cell Signaling, Ecological Principles, etc.
Mathematical Sciences: Analysis Linear Algebra, Complex Analysis Algebra, Topology, Ordinary Differential Equations (ODEs), Partial Differential Equations (PDEs), Numerical Analysis, Calculus of Variations, Linear Integral Equations, Classical Mechanics, Statistics, Exploratory Data Analysis, etc.
Physical Sciences: Mathematical Methods of Physics, Classical Mechanics, Electromagnetic Theory, Quantum Mechanics, Thermodynamic and Statistical Physics, Electronics and Experimental Methods, Atomic and Molecular Physics, Condensed Matter Physics, Nuclear and Particle Physics, etc.
Also Read: CSIR NET 2025 Answer Key
CSIR NET 2025 Admit Card
The National Testing Agency (NTA) will release the CSIR NET Admit Card 2025 approximately three days before the exam date. Candidates will be able to download the CSIR NET admit card from the official website. The admit card has details of the examination like the examination centre, exam date, schedule, time of examination, etc. Check below for the steps required to download the CSIR NET 2025 admit card.
- Visit the official website; csirnet.nta.ac.in
- On the homepage, click on the CSIR-UGC NET December Admit Card 2025 link
- A new webpage will open.
- Candidates should enter the required details to download the admit card
- If everything is done perfectly, the candidate’s admit card will be displayed on the screen
- Download the admit card and print it out for future use
Also Read: CSIR NET 2024 (All Day) Exam Analysis: Subject-Wise Question Paper Difficulty Level & Answer Key PDF
CSIR NET 2025 Provisional Answer Key
The authority will release the CSIR NET Provisional Answer Key 2025 on the official website at csirnet.nta.ac.in. It will consist of the correct answers to the questions asked in the CSIR NET exam 2025. Candidates can check their answers and determine their scores. The CSIR NET 2025 Answer Key will be released in two stages: first, the CSIR NET Provisional Answer Key and second, the CSIR NET Final Answer Key.
Steps To Download The CSIR NET Provisional Answer Key 2025
Candidates can check below the steps to download the CSIR NET 2025 Answer Key.
- Visit the official website, csirnet.nta.ac.in.
- Check the CSIR NET Answer Key Link 2025 on the homepage or in the Latest Update section.
- Click on the link and Proceed.
- Choose the CSIR NET exam session and the subject for which you appeared in the exam.
- The CSIR NET 2025 Answer key will be displayed on the screen.
- Download it and calculate your probable scores.
CSIR NET 2025 Final Answer Key
The CSIR NET 2025 Final Answer Key will be released by the authority after considering all the challenges raised by the candidates who appeared in the exam.
Check CSIR NET 2025 June Final Answer Key: To be updated here
Also Read: CSIR NET Exam Centres List
CSIR NET 2025 Analysis
Here we will provide the CSIR NET 2025 June session analysis after the exam based on the reaction of the students. It will include the overall difficulty level of the exam, topics asked in the exam, cutoff, etc.
Also Read:
CSIR NET 2025 Result
The CSIR NET Result 2025 for the June session will be announced on the official website at csirnet.nta.ac.in. Candidates who appeared for the exam will be able to check CSIR UGC NET result 2025 by logging in with the application number and date of birth. The CSIR NET e-certificate 2025 will be distributed based on the final results declared by the CSIR. The CSIR NET cut-off 2025 will be released by the CSIR on the official website.
Steps To Check CSIR NET 2025 Result
Scroll down to know the steps for downloading the CSIR NET 2025 Result.
- Open the official website of CSIR NET; csirnet.nta.ac.in
- Click on the 'CSIR UGC NET 2025 June Result' link
- Enter the following details: Application number, Date of birth & Security pin as shown in the image
- Click on Submit
- View and download the CSIR NET result and scorecard
CSIR UGC NET June Result 2025 Download Link- to be notified
CSIR NET 2025 Certificate
The applicants who pass the exam and become eligible for JRF and lectureship are given CSIR NET Certificate.
Steps to Download the CSIR NET Certificate 2025
- Visit the official website
- Click 'Joint CSIR UGC NET', enter the captcha code and submit
- Enter your Roll number and Date of Birth
- Download and Save the PDF
CSIR NET 2025 Cut-Off
The National Testing Agency (NTA) will announce the CSIR NET Subject-wise Cut-off and the result. Candidates will be able to download the subject-wise CSIR NET Cut-Off through the official website. The NTA will release the CSIR NET Subject-wise Cutoff in PDF format. The subject-wise cut-off for CSIR NET will be shared here also once it is released.
How to Check CSIR NET Cutoff 2025?
Candidates can follow the below-mentioned steps to check the cut-off for the CSIR UGC NET exam:
- Visit the official website of CSIR; csirhrdg.res.in
- Click on the 'Cut-off' link available under the News & Announcement section
- Download and save the CSIR NET cutoff list
CSIR UGC NET June Cut-off 2025 Official PDF: to be notified
Read More: CSIR NET Preparation Tips 2025
Shikha Goyal is an author with expertise in various domains, especially engineering. She has postgraduate degrees in Mathematics as well as Mass Communication and Journalism. She has devoted her life to helping stud... Read Full Bio
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Student Forum
Answered a week ago
CSIR NET exam includes 5 subjects. These subjects are Life Science, Physical Science, Earth Science, Chemical Science, and Mathematics. Candidates must select one subject from the CSIR NET subject list to crack the exam.
Preparation of CSIR NET Life Science without coaching can be a daunting task, bu
N
Contributor-Level 6
Answered a month ago
Hi Smita,
The CSIR NET December 2024 application process has been extended until January 2, 2025. Interested candidates can apply online through the official website: csirnet.nta.ac.in
Important Dates:
Application Deadline: January 2, 2025
Fee Payment Deadline: January 3, 2025
Correction Window: Janu
A
Contributor-Level 9
Answered a month ago
The December session of the CSIR NET 2024 exam will take place from February 28 to March 2, 2025. The detailed schedule and exact timings of the examination has been released on the official website.
S
Beginner-Level 2
Answered 2 months ago
The CSIR NET 2024 December cut off will be released by the Council of Scientific and Industrial Research (CSIR) in an online mode on the official website. It will be released subject-wise separately for the CSIR UGC NET 2024 December exam. The cut-off for CSIR NET is the minimum marks required by th
S
Contributor-Level 10
To pass the CSIR NET 2024 exam, candidates are required to score a minimum of 33 percent in the general, EWS, and OBC categories and 25 percent in the SC, ST, and PwD categories, or both fellowship and Lectureship/Assistant Professor.